我正在构建一个Angular 5应用程序来跟踪利润。 我的应用程序有多个输入字段。
如果我卖巧克力,那么我会按+按钮增加计数。
如果我卖Wine,那么我会按下Wine输入旁边的+按钮来增加计数。
现在我使用了incrementchoc()函数来增加巧克力的数量 和incrementwine()函数增加葡萄酒的数量。
以下是我的HTML:
<div >
<label>Chocolate:</label><br>
<div class="input-group">
<span class="input-group-btn">
<button type="button" class="btn btn-danger btn-number" (click)= "decrementchoc()" data-type="minus" data-field="quant[2]">
<span class="glyphicon glyphicon-minus"></span>
</button>
</span>
<input type="text" name="quant[2]" [(ngModel)]="info.choco" (keyup)="choc(info.choco)" class="form-control input-number" value="{{info.choco}}" >
<span class="input-group-btn">
<button type="button" class="btn btn-success btn-number" (click)= "incrementchoc()" data-type="plus" data-field="quant[2]">
<span class="glyphicon glyphicon-plus"></span>
</button>
</span>
</div></div>
<div >
<label>Wine:</label><br>
<div class="input-group">
<span class="input-group-btn">
<button type="button" class="btn btn-danger btn-number" (click)= "decrementwine()" data-type="minus" data-field="quant[3]">
<span class="glyphicon glyphicon-minus"></span>
</button>
</span>
<input type="text" name="quant[3]" [(ngModel)]="info.wine" (keyup)="wine(info.wine)" class="form-control input-number" value="{{info.wine}}" >
<span class="input-group-btn">
<button type="button" class="btn btn-success btn-number" (click)= "incrementwine()" data-type="plus" data-field="quant[3]">
<span class="glyphicon glyphicon-plus"></span>
</button>
</span>
</div></div>
我也附上了一张照片。 This is how my HTML looks like with the - and + buttons
以下是我的Component.ts文件的代码
incrementchoc(){
this.info.choco= ++this.info.choco;
}
decrementchoc(){
this.info.choco= --this.info.choco;
}
incrementwine(){
this.info.wine= ++this.info.wine;
}
decrementwine(){
this.info.wine= --this.info.wine;
}
从上面的代码可以清楚地看到,如果我有n个输入字段,那么我将不得不写入n个递增和递减函数。我认为这会使应用程序非常繁重。
请建议我通过使用单个函数增加递减值,通过检测输入的ngModel并仅递增/递减该值而不是写入n个函数来建议我这样做。
答案 0 :(得分:2)
您可以直接在组件模板中执行递增和递减操作。您不需要使用组件代码。
例如:
<button type="button" class="btn btn-danger btn-number"
(click)="info.choco = info.choco - 1" data-type="minus" data-field="quant[2]">
<span class="glyphicon glyphicon-minus"></span>
</button>
完整代码:
<div>
<label>Chocolate:</label><br>
<div class="input-group">
<span class="input-group-btn">
<button type="button" class="btn btn-danger btn-number"
(click)="info.choco = info.choco - 1" data-type="minus" data-field="quant[2]">
<span class="glyphicon glyphicon-minus"></span>
</button>
</span>
<input type="text" name="quant[2]" class="form-control input-number"
[(ngModel)]="info.choco" (keyup)="choc(info.choco)" value="{{info.choco}}" >
<span class="input-group-btn">
<button type="button" class="btn btn-success btn-number"
(click)="info.choco = info.choco + 1" data-type="plus" data-field="quant[2]">
<span class="glyphicon glyphicon-plus"></span>
</button>
</span>
</div>
</div>
<div>
<label>Wine:</label><br>
<div class="input-group">
<span class="input-group-btn">
<button type="button" class="btn btn-danger btn-number"
(click)="info.wine = info.wine - 1" data-type="minus" data-field="quant[3]">
<span class="glyphicon glyphicon-minus"></span>
</button>
</span>
<input type="text" name="quant[3]" class="form-control input-number"
[(ngModel)]="info.wine" (keyup)="wine(info.wine)" value="{{info.wine}}">
<span class="input-group-btn">
<button type="button" class="btn btn-success btn-number"
(click)="info.wine = info.wine + 1" data-type="plus" data-field="quant[3]">
<span class="glyphicon glyphicon-plus"></span>
</button>
</span>
</div>
</div>
答案 1 :(得分:0)
是的,目前的方法使它变得沉重。你可以这样做:
increment(value: string) {
if(value === 'wine') {
this.info.wine = ++this.info.wine;
}else if (value === 'choc'){
this.info.choco= ++this.info.choco;
}else{
this.info.gir = ++this.info.gir;
}
}
<button type="button" class="btn btn-success btn-number" (click)= "incrementwine(wine)" data-type="plus" data-field="quant[3]">
<span class="glyphicon glyphicon-plus"></span>
</button>
相同的减量
*我没有检查代码的逻辑。只是重构。