我需要帮助创建一个查询,将一个数据库中的Equipment
与另一个表中的Asset
进行比较。这是我的数据库设置:
CREATE DATABASE database1
GO
USE [database1]
GO
CREATE TABLE [dbo].[Application]
(
[ApplicationID] [int] IDENTITY(1,1) NOT NULL PRIMARY KEY,
[APP_NUMBRER] [int] NULL,
)
GO
CREATE TABLE [dbo].[Equipment]
(
[EquipID] [int] IDENTITY(1,1) NOT NULL,
[ApplicationID] [int] NULL,
[Year] [varchar](4) NULL,
[Make] [varchar](50) NULL,
[Model] [varchar](50) NULL
)
ALTER TABLE [dbo].[Equipment] WITH CHECK
ADD CONSTRAINT [FK_EQUIP_1]
FOREIGN KEY([ApplicationID]) REFERENCES [dbo].[APPLICATION] ([ApplicationID])
GO
INSERT INTO [Application]
VALUES (1), (2), (3)
INSERT INTO [Equipment]
VALUES (1, '1998', 'Equip1', 'Model1'),
(1, '1855', 'Equip2', 'Model2'),
(2, '1222', 'Equip3', 'Model4'),
(2, '1333', 'Equip4', 'Model4'),
(3, '1777', 'Equip5', 'Model5')
GO
CREATE DATABASE database2
GO
USE [database2]
GO
CREATE TABLE [dbo].[Application]
(
[APP_KEY] [int] IDENTITY(1,1) NOT NULL PRIMARY KEY,
[APP_DESCRIPTION] [varchar](40) NOT NULL
)
GO
CREATE TABLE [dbo].[ASSET]
(
[AS_KEY] [int] IDENTITY(1,1) NOT NULL PRIMARY KEY,
[AS_APP_FKEY] [int] NOT NULL,
[Year] [varchar](4) NULL,
[Make] [varchar](50) NULL,
[Model] [varchar](50) NULL
)
ALTER TABLE [dbo].[ASSET] WITH CHECK
ADD CONSTRAINT [FK_ASSET_1]
FOREIGN KEY([AS_APP_FKEY]) REFERENCES [dbo].[APPLICATION] ([APP_KEY])
GO
INSERT INTO [Application]
VALUES ('AppDesc1'), ('AppDesc2')
INSERT INTO [ASSET]
VALUES (1, '1998', 'Asset1', 'Db2Model1'),
(1, '1855', 'Asset2', 'Db2Model2'),
(2, '1222', 'Asset3', 'Db2Model3'),
(2, '1333', 'Asset4', 'Db2Model4')
GO
我的查询:
SELECT
ap1.APP_NUMBRER,
e.Year, e.Make, e.Model,
db2.APP_KEY, db2.Year, db2.Make, db2.Model
FROM
database1.dbo.Application ap1
JOIN
database1.dbo.Equipment e ON E.APPLICATIONID = ap1.APPLICATIONID
LEFT JOIN
(SELECT
APP_KEY, Year, Make, Model
FROM
[database2].dbo.APPLICATION ap2
JOIN
[database2].dbo.ASSET ON asset.AS_APP_FKEY = ap2.APP_KEY) db2 ON ap1.APP_NUMBRER = db2.APP_KEY
结果:
预期结果:我的查询正在创建一些重复项,将所有db1设备与db2资产进行比较。我希望进行一对一的比较。我不想要2,3,6,7项。这是因为表关系的设置方式。
答案 0 :(得分:1)
这是因为您只加入APP_NUMBER=APP_KEY
。将Year=Year
添加到JOIN,您将获得所需的结果。
答案 1 :(得分:0)
在您加入时添加YEAR
。它会解决你的问题。
SELECT ap1.APP_NUMBRER, e.Year, e.Make, e.Model, db2.APP_KEY, db2.Year, db2.Make, db2.Model
FROM database1.dbo.Application ap1
JOIN database1.dbo.Equipment e
ON E.APPLICATIONID = ap1.APPLICATIONID
LEFT JOIN(
SELECT APP_KEY, Year, Make, Model
FROM [database2].dbo.APPLICATION ap2
JOIN [database2].dbo.ASSET
ON asset.AS_APP_FKEY = ap2.APP_KEY
) db2
ON ap1.APP_NUMBRER = db2.APP_KEY AND e.Year = db2.Year
答案 2 :(得分:0)
像这样修改您的JOIN条件
db2 ON ap1.APP_NUMBRER = db2.APP_KEY
AND e.Year = db2.Year