Question

我正在尝试通过TinyMCE上传图像，但是在编辑器本身中显示“HTTP Error：403”。我分别从网站上获取了脚本和php页面的代码：

tinymce.init({
      selector: "textarea",
      plugins: "link image",

      height:300,
      setup: function (editor) {
        editor.on('change', function () {editor.save();});

      },

    images_upload_handler: function (blobInfo, success, failure) {
    var xhr, formData;

    xhr = new XMLHttpRequest();
    xhr.withCredentials = false;
    xhr.open('POST', 'queries/editorImageUpload.php');

    xhr.onload = function() {
      var json; 

      if (xhr.status != 200) {
        failure('HTTP Error: ' + xhr.status);
        return;
      }

      json = JSON.parse(xhr.responseText);

      if (!json || typeof json.location != 'string') {
        failure('Invalid JSON: ' + xhr.responseText);
        return;
      }

      success(json.location);
    };

    formData = new FormData();
    formData.append('file', blobInfo.blob(), blobInfo.filename());

    xhr.send(formData);
  }

});

然后在'editorImageUpload.php'中，我认为问题与$ accepted_origins部分有关，因为它返回403错误：

$accepted_origins = array("https://localhost", "https://77.104.172.194");

  $imageFolder = "pictures/Test/";

  reset ($_FILES);
  $temp = current($_FILES);
  if (is_uploaded_file($temp['tmp_name'])){

    if (isset($_SERVER['HTTP_ORIGIN'])) {
      // same-origin requests won't set an origin. If the origin is set, it must be valid.
      if (in_array($_SERVER['HTTP_ORIGIN'], $accepted_origins)) {
        header('Access-Control-Allow-Origin: ' . $_SERVER['HTTP_ORIGIN']);
      } else {
        header("HTTP/1.1 403 Origin Denied");
        return;
      }
    }

对此的任何见解都会非常有用。

Answer 1

首先，您的代码有两个问题 - 你的PHP代码不会将图像传输到服务器
- 在你的PHP代码中，你正在使用＆＃34; https://localhost＆＃34;制作$ accepted_origins数组。你忘记了不安全的版本＆＃34; http://localhost＆＃34;

所以最快的解决方法是编写有效的PHP代码，将图像传输到服务器并返回图像完整路径，编辑器在这里是php代码

<强> editorImageUpload.php

<?php 
      $ds = DIRECTORY_SEPARATOR;

      $storeFolder = 'images';

      if (!empty($_FILES)) 
      {
             $tempFile = $_FILES['file']['tmp_name'];

             $targetPath = dirname( __FILE__ ) . $ds. $storeFolder . $ds;

             $file_name = substr(md5(rand(1, 213213212)), 1, 5) . "_" . str_replace(array('\'', '"', ' ', '`'), '_', $_FILES['file']['name']);

             $targetFile =  $targetPath. $file_name;

             if(move_uploaded_file($tempFile,$targetFile)){
                   die( $_SERVER['HTTP_REFERER']. $storeFolder . "/" . $file_name );
              }else{
                   die('Fail');
              }

       }
?>

并且在你的javascript回调中你必须检查xhr.response而不是xhr.responseText，因为你正在死于图像的完整路径

Tinymce代码

 tinymce.init({
      selector: "textarea",
      plugins: "link image",
      height:300,

      images_upload_handler: function (blobInfo, success, failure) {
            var xhr, formData;

            xhr = new XMLHttpRequest();
            xhr.withCredentials = false;
            xhr.open('POST', 'editorImageUpload.php');

            xhr.onload = function() {
              var json; 

              if (xhr.status != 200) {
                failure('HTTP Error: ' + xhr.status);
                return;
              }

              console.log(xhr.response);
              //your validation with the responce goes here

              success(xhr.response);
            };

            formData = new FormData();
            formData.append('file', blobInfo.blob(), blobInfo.filename());

            xhr.send(formData);
       }

 });

尝试使用TinyMCE上传图片时出现错误403

1 个答案: