Question

如果在for循环

中重复相同的id，我试图对这些值求和

<?php 
    $tax = count($_POST['tax_id']);
    for($i=0;$i<$tax;$i++) { 
        $tax_id = $_POST['tax_id'][$i]; 
        $tax_amount = $_POST['amount'][$i];
        $sql = "SELECT * FROM `ca_taxmaster` where tax_comp = $tax_id ";
        $now = mysql_query($sql) or die(mysql_error()); 
        while($row1 = mysql_fetch_array($now)){
            $per = $row1['tax_Percent'];            
            $tax_calc = ($tax_amount*$per)/100;
            $sum_total += $tax_calc;
?>

<tr>
    <td class="text-right" colspan="5"><b><?php echo $row1['tax_type']; ?></b></td>
    <td class="text-right"></td>
    <td class="text-right"><?php echo $tax_calc;?></td>
</tr>

<?php } } ?>

我的输出就像在Gst的税收栏中我有sgst＆amp; cgst如果我选择第二次我需要sgst＆amp; cgst的总和

  No.   Job          Description    SAC Code        Tax       Amount
   0    teaching           desc1    sa001           GST     -   1000
   1    engineer           desc2    sac002    IGST-Master   -   2000
   2    doctor             desc3    sac003          GST     -   1000
                                               Sub-Total        Rs.4000
                                                    SGST        90
                                                    CGST        90
                                                    IGST        360
                                                    SGST        90
                                                    CGST        90
                                                   Total        Rs.4720

但我需要得到如果相同的id重复它应该总和值

                                                    SGST        180
                                                    CGST        180
                                                    IGST        360
                                                   Total        Rs.4720

和我的sql结构如下： sql table structure

如果还有其他办法，请帮帮我。谢谢提前

Answer 1

根据您共享的表格结构，您可以使用此查询替换您的查询：

SELECT sum(tax_Percent) 
FROM ca_taxmaster where tax_comp = $tax_id 
GROUP BY tax_type;

Answer 2

你可以试试这个：

<?php 
    $tax = count($_POST['tax_id']);
    $sum_total = 0;
    for($i=0;$i<$tax;$i++) { 
        $tax_id = $_POST['tax_id'][$i]; 
        $tax_amount = $_POST['amount'][$i];
        $sql = "SELECT * FROM `ca_taxmaster` where tax_comp = $tax_id ";
        $now = mysql_query($sql) or die(mysql_error()); 
        while($row1 = mysql_fetch_array($now)){
            $per = $row1['tax_Percent'];            
            $tax_calc = ($tax_amount*$per)/100;
            $sum_total = $sum_total  + $tax_calc;
?>

<tr>
    <td class="text-right" colspan="5"><b><?php echo $row1['tax_type']; ?></b></td>
    <td class="text-right"></td>
    <td class="text-right"><?php echo $tax_calc;?></td>
</tr>

<?php } } ?>

如果相同的id重复，如何获得总和

2 个答案: