Question

如何使用indexOf（）和CharAt（）方法显示输出？ “B R A M”

public class Test {

public static void main(String[] args) {

    String s = new String("Business Requirement And Management");
    String shortForm = "";
    int index = 0;
    int i=0;

    while(i<s.length()) {
        if(s.charAt(i) == ' '){
        index = s.indexOf(" ");
        shortForm +=  s.charAt(index+1);
        }
        i++;
    }
    System.out.println(shortForm);         

}
}

Answer 1

我会用这样的东西：

StringBuilder sb = new StringBuilder();
String s = "Business Requirement And Management";
String[] splitted = s.split("\\s");
for(String str : splitted)
{
    sb.append(str.charAt(0)).append(" ");
}
System.out.println(sb.toString());

<强>解释

我们通过调用split("\s")将字符串溢出到每个空白字符并存储新的＆＃34;子字符串＆＃34;在数组中。现在迭代数组并获取每个字符串的第一个字符并将其附加到String。如果您希望确定首字母大写，则可以使用System.out.println(sb.toString().toUpperCase())。

Answer 2

public class Test {

   public static void main(String[] args) {

    String s = new String("Business Requirement And Management");
    String shortForm = "";
    int index = 0;

    while(s.length() > 0) {
        index = s.indexOf(" ");
        if(index == -1 || index == s.length() -1) break;
        shortForm +=  s.charAt(index+1);
        s = s.substring(index+1);

    }
    System.out.println(shortForm);         
  }
}

简短形式的单词

2 个答案: