Question

我有以下数据集

Data = data.frame(id =c(1,1), 
dob=c("06/06/2018", "06/06/2018"), 
reason=c("age", "disability"))

我需要删除所有重复的ID，其原因为年龄

尝试以下但确实有效

Final_data = data[which(! duplicate (id)) & which( reason=="age"),]

有人可以帮助我，我是R的新手

Answer 1

which返回整数位置。相反，&可以直接应用于逻辑条件

Data[!duplicated(Data$id) &  Data$reason=="age",]
#  id        dob reason
#1  1 06/06/2018    age

更新

基于新数据

library(dplyr)
Data %>% 
   group_by(id) %>% f
   ilter(reason != "age"| n()==1)
# A tibble: 3 x 3
# Groups: id [3]
#     id dob        reason    
#  <dbl> <chr>      <chr>     
#1  1.00 06/08/2018 disability
#2  2.00 08/08/1992 disability
#3  3.00 09/01/1995 age

或data.table

library(data.table)
setDT(Data)[, .SD[reason != 'age'| .N == 1], id]

数据

Data <- data.frame(id = c(1,1,2, 2,3),
   dob=c("06/08/2018","06/08/2018", "08/08/1992", "08/08/1992", "09/01/1995"),
  reason= c("age","disability","age","disability","age"), stringsAsFactors = FALSE)

Answer 2

在base-R中：

Data[!(Data$dob %in% Data$dob[duplicated(Data$dob)] & Data$reason == "age"),]

  # id        dob     reason
  # 2  1 06/08/2018 disability
  # 4  2 08/08/1992 disability
  # 5  3 09/01/1995        age

数据

Data = data.frame( id = c(1,1,2,2,3), dob=c("06/08/2018","06/08/2018", "08/08/1992", "08/08/1992", "09/01/1995"), reason= c("age","disability","age","disability","age"))

删除条件重复

2 个答案:

更新

数据