我有以下json,我想再添加一个属性:
[ {
"A": 1,
"B": "str"
},
{
"A": 2,
"B": "str2"
},
{
"A": 3,
"B": "str3"
}
]
所以我想要这样的事情:
[ {
"A": 1,
"B": "str",
"C": "X"
},
{
"A": 2,
"B": "str2",
"C": "X"
},
{
"A": 3,
"B": "str3",
"C": "X"
}
]
这样做的最佳方式是什么?
答案 0 :(得分:3)
遍历列表中的每个dict obj并添加list1 = [
{
"A": 1,
"B": "str"
},
{
"A": 2,
"B": "str2"
},
{
"A": 3,
"B": "str3"
}
]
:
列出之前
for l in list1:
l['C'] = 'X'
print(list1)
代码
[{'A': 1, 'B': 'str', 'C': 'X'}, {'A': 2, 'B': 'str2', 'C': 'X'}, {'A': 3, 'B': 'str3', 'C': 'X'}]
列表输出
df.first.get(0).toString
//res0: String = 1
df.first.get(0).toString.toLong
//res1: Long = 1
df.first.get(0).toString.toFloat
//res2: Float = 1.0
答案 1 :(得分:2)
>>> j = [ { "A": 1, "B": "str" }, { "A": 2, "B": "str2" }, { "A": 3, "B": "str3" } ]
>>> [i.update({'C': 'X'}) for i in j]
>>> j
[{'A': 1, 'B': 'str', 'C': 'X'}, {'A': 2, 'B': 'str2', 'C': 'X'}, {'A': 3, 'B': 'str3', 'C': 'X'}]
或者,根据coldspeed的评论:
>>> for item in j:
... item['C'] = 'X'
...
>>> j
[{'A': 1, 'B': 'str', 'C': 'X'}, {'A': 2, 'B': 'str2', 'C': 'X'}, {'A': 3, 'B': 'str3', 'C': 'X'}]