Question

后台：我正在为我的学校项目设计一个简单的GUI应用程序，该应用程序具有基本的CRUD功能，用户可以将基本事务键入相关的文本字段，记录将是分发到数据库中。

问题：现在，Create，Retrieve和Delete功能完美运行，没有任何错误。现在的问题是更新功能不起作用。我无法确定它是JPanel中我的方法中的错误，还是我的数据访问文件中的方法。

注意：所有数据库列表都拼写正确，因为我可以创建记录。

JPanel方法

private void updatingTransaction() {
   String tName = UpdateTransaction.txtTName.getText();
   String tID = UpdateTransaction.txtTID.getText();
   String tDetail = UpdateTransaction.txtTDetail.getText();
   String pName = UpdateTransaction.txtPName.getText();
   String pNRIC = UpdateTransaction.txtPNRIC.getText();
   String pDate = UpdateTransaction.txtPDate.getText();
   String pContact = UpdateTransaction.txtPContact.getText();
   String pEmail = UpdateTransaction.txtPEmail.getText();
   String pOrganisation = UpdateTransaction.txtPOrganisation.getText();

   Transaction updateTransaction = new Transaction(tName, tID, tDetail, pName, pNRIC, pDate, pContact, pEmail, pOrganisation);

   if (TransactionDA.updateTransaction(updateTransaction)) {
     JOptionPane.showMessageDialog(TransFrame, "Record successfully updated.");
   } else {
     JOptionPane.showMessageDialog(TransFrame, "Sorry, there seems to be an error in updating the record.");
   }
}

数据访问方法

public static boolean updateTransaction(Transaction transaction) {
    boolean success = false;
    DBControl db = new DBControl();
    String dbQuery; 
    PreparedStatement pstmt;

    db.getConnection();     

    dbQuery = "UPDATE transactioninfo SET tName = ?, tID = ?, tDetail = ?, pName = ?, pNRIC = ?, pDate = ?, pContact = ?, pEmail = ?, pOrganisation = ? WHERE id = ?";
    pstmt = db.getPreparedStatement(dbQuery);

    try {
        pstmt.setString(1, transaction.gettName());
        pstmt.setString(2, transaction.gettID());
        pstmt.setString(3, transaction.gettDetail());
        pstmt.setString(4, transaction.getpName());
        pstmt.setString(5, transaction.getpNRIC());
        pstmt.setString(6, transaction.getpDate());
        pstmt.setString(7, transaction.getpContact());
        pstmt.setString(8, transaction.getpEmail());
        pstmt.setString(9, transaction.getpOrganisation());
        pstmt.setInt(10, transaction.getId());
        if (pstmt.executeUpdate() == 1)
            success = true;
        pstmt.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
    System.out.println(success);
    db.terminate();

    return success;     
}

Answer 1

尝试通过添加

来提交连接

YourConnection.commit();

pstmt.executeUpdate（）;

之后

Answer 2

好吧，这些是我对updatesTransaction所做的更改。

private void updateTheTransaction(int id) {

   String tName = UpdateTransaction.txtTName.getText();
   String tID = UpdateTransaction.txtTID.getText();
   String tDetail = UpdateTransaction.txtTDetail.getText();
   String pName = UpdateTransaction.txtPName.getText();
   String pNRIC = UpdateTransaction.txtPNRIC.getText();
   String pDate = UpdateTransaction.txtPDate.getText();
   String pContact = UpdateTransaction.txtPContact.getText();
   String pEmail = UpdateTransaction.txtPEmail.getText();
   String pOrganisation = UpdateTransaction.txtPOrganisation.getText();

   Transaction updateTransaction = new Transaction(id+1, tName, tID, tDetail, pName, pNRIC, pDate, pContact, pEmail, pOrganisation);

   if (TransactionDA.updateTransaction(updateTransaction)) {
     JOptionPane.showMessageDialog(TransFrame, "Record successfully updated.");
   } else {
     JOptionPane.showMessageDialog(TransFrame, "Sorry, there seems to be an error in updating the record.");
   }
}

并且，因为我使用JButton调用该方法，所以我将这些代码行添加到按钮方法

btnDone.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent arg0) {
        int selectedIndex = 0;
            updateTransaction(selectedIndex);

    }

});

MySQL Update Statement无效

2 个答案: