Question

ex: "32 ½ is not very hot " to x = "info: 32, numerator = 1, denominator = 2"

Note: it could be 3/9, but it cannot be simplified into 1/3 aka literally get what is in the string.

I need to detect the fractional string in a longer string and expand the information to a more usable form.

½ has been given to me decoded and is a string with length one.

Answer 1

There seem to be 19 such forms (here) and they all start with the name VULGAR FRACTION.

import unicodedata

def fraction_finder(s):
    for c in s:
        try:
            name = unicodedata.name(c)
        except ValueError:
            continue
        if name.startswith('VULGAR FRACTION'):
            normalized = unicodedata.normalize('NFKC', c)
            numerator, _slash, denominator = normalized.partition('⁄')
            yield c, int(numerator), int(denominator)

Demo:

>>> s = "32 ½ is not very hot "
>>> print(*fraction_finder(s))
('½', 1, 2)

Detect single string fraction (ex: ½ ) and change it to longer string?

1 个答案: