i ran into an interesting bug when writing a json parser(called /home/myusername/py/json.py) in python3 i raised a basic exception and got unexpected output,
when investigating this further i wrote a new script entirely given below
raise Exception("basic exception")
after running "python3 error.py" i should get a really short error message, but instead i get console output of the previous run program.
[unexpected debug output of json.py]
[truncated for readability]
[it is extremely long but does not contain further errors]
Traceback (most recent call last):
File "error.py", line 1, in <module>
raise Exception("basic exception")
Exception: basic exception
Error in sys.excepthook:
Traceback (most recent call last):
File "/usr/lib/python3/dist-packages/apport_python_hook.py", line 63, in apport_excepthook
from apport.fileutils import likely_packaged, get_recent_crashes
File "/usr/lib/python3/dist-packages/apport/__init__.py", line 5, in <module>
from apport.report import Report
File "/usr/lib/python3/dist-packages/apport/report.py", line 30, in <module>
import apport.fileutils
File "/usr/lib/python3/dist-packages/apport/fileutils.py", line 23, in <module>
from apport.packaging_impl import impl as packaging
File "/usr/lib/python3/dist-packages/apport/packaging_impl.py", line 17, in <module>
import json
File "/home/myusername/py/json.py", line 174, in <module>
rs = parser.Object(testcase)
File "/home/myusername/py/json.py", line 104, in Object
raise Exception(self.Array(source, "crashing object scanner"))
Exception: None
Original exception was:
Traceback (most recent call last):
File "error.py", line 1, in <module>
raise Exception("basic exception")
Exception: basic exception
i dont know why i get such a long message. nor do i know why i get debug code of an uncalled script. i would like an explanation, i am running Ubuntu, i have not yet found related bugs on the internet.
答案 0 :(得分:0)
基本的异常处理似乎需要一个json.py脚本,所以当我的error.py引发异常时,它会加载我的json.py脚本而不是buildin脚本,那么我的json脚本会出现异常。
解决方案是重命名我的json.py