是否有任何优雅的快速方法将对象映射到字典,反之亦然?
IDictionary<string,object> a = new Dictionary<string,object>();
a["Id"]=1;
a["Name"]="Ahmad";
// .....
变为
SomeClass b = new SomeClass();
b.Id=1;
b.Name="Ahmad";
// ..........
答案 0 :(得分:151)
在两种扩展方法中使用一些反射和泛型可以实现这一点。
是的,其他人做了大部分相同的解决方案,但这使用较少的反射,这在性能方面更具可读性:
public static class ObjectExtensions
{
public static T ToObject<T>(this IDictionary<string, object> source)
where T : class, new()
{
var someObject = new T();
var someObjectType = someObject.GetType();
foreach (var item in source)
{
someObjectType
.GetProperty(item.Key)
.SetValue(someObject, item.Value, null);
}
return someObject;
}
public static IDictionary<string, object> AsDictionary(this object source, BindingFlags bindingAttr = BindingFlags.DeclaredOnly | BindingFlags.Public | BindingFlags.Instance)
{
return source.GetType().GetProperties(bindingAttr).ToDictionary
(
propInfo => propInfo.Name,
propInfo => propInfo.GetValue(source, null)
);
}
}
class A
{
public string Prop1
{
get;
set;
}
public int Prop2
{
get;
set;
}
}
class Program
{
static void Main(string[] args)
{
Dictionary<string, object> dictionary = new Dictionary<string, object>();
dictionary.Add("Prop1", "hello world!");
dictionary.Add("Prop2", 3893);
A someObject = dictionary.ToObject<A>();
IDictionary<string, object> objectBackToDictionary = someObject.AsDictionary();
}
}
答案 1 :(得分:11)
似乎反射只有帮助。我已经完成了将对象转换为字典的小例子,反之亦然:
[TestMethod]
public void DictionaryTest()
{
var item = new SomeCLass { Id = "1", Name = "name1" };
IDictionary<string, object> dict = ObjectToDictionary<SomeCLass>(item);
var obj = ObjectFromDictionary<SomeCLass>(dict);
}
private T ObjectFromDictionary<T>(IDictionary<string, object> dict)
where T : class
{
Type type = typeof(T);
T result = (T)Activator.CreateInstance(type);
foreach (var item in dict)
{
type.GetProperty(item.Key).SetValue(result, item.Value, null);
}
return result;
}
private IDictionary<string, object> ObjectToDictionary<T>(T item)
where T: class
{
Type myObjectType = item.GetType();
IDictionary<string, object> dict = new Dictionary<string, object>();
var indexer = new object[0];
PropertyInfo[] properties = myObjectType.GetProperties();
foreach (var info in properties)
{
var value = info.GetValue(item, indexer);
dict.Add(info.Name, value);
}
return dict;
}
答案 2 :(得分:10)
首先使用Newtonsoft将Dictionary转换为JSON字符串。
var json = JsonConvert.SerializeObject(advancedSettingsDictionary, Newtonsoft.Json.Formatting.Indented);
然后将JSON字符串反序列化为对象
var myobject = JsonConvert.DeserializeObject<AOCAdvancedSettings>(json);
答案 3 :(得分:9)
我强烈推荐Castle DictionaryAdapter,这是该项目保存最好的秘密之一。您只需要定义一个具有所需属性的接口,并在一行代码中,适配器将生成一个实现,实例化它,并将其值与您传入的字典同步。我用它来强类型我的AppSettings in一个网络项目:
var appSettings =
new DictionaryAdapterFactory().GetAdapter<IAppSettings>(ConfigurationManager.AppSettings);
请注意,我不需要创建一个实现IAppSettings的类 - 适配器即时执行。此外,虽然在这种情况下我只是阅读,理论上如果我在appSettings上设置属性值,适配器会使基础字典与这些更改保持同步。
答案 4 :(得分:5)
通过遍历属性,反射可以将您从对象带到字典。
换句话说,你必须在C#中使用动态ExpandoObject(实际上已经从IDictionary继承了,所以已经为你完成了这个),除非你能推断出类型以某种方式从字典中的条目集合。
所以,如果你在.NET 4.0中,请使用ExpandoObject,否则你需要做很多工作......
答案 5 :(得分:3)
我认为你应该使用反思。像这样:
private T ConvertDictionaryTo<T>(IDictionary<string, object> dictionary) where T : new()
{
Type type = typeof (T);
T ret = new T();
foreach (var keyValue in dictionary)
{
type.GetProperty(keyValue.Key).SetValue(ret, keyValue.Value, null);
}
return ret;
}
它需要你的字典并循环遍历它并设置值。你应该做得更好,但这是一个开始。你应该这样称呼它:
SomeClass someClass = ConvertDictionaryTo<SomeClass>(a);
答案 6 :(得分:2)
public class SimpleObjectDictionaryMapper<TObject>
{
public static TObject GetObject(IDictionary<string, object> d)
{
PropertyInfo[] props = typeof(TObject).GetProperties();
TObject res = Activator.CreateInstance<TObject>();
for (int i = 0; i < props.Length; i++)
{
if (props[i].CanWrite && d.ContainsKey(props[i].Name))
{
props[i].SetValue(res, d[props[i].Name], null);
}
}
return res;
}
public static IDictionary<string, object> GetDictionary(TObject o)
{
IDictionary<string, object> res = new Dictionary<string, object>();
PropertyInfo[] props = typeof(TObject).GetProperties();
for (int i = 0; i < props.Length; i++)
{
if (props[i].CanRead)
{
res.Add(props[i].Name, props[i].GetValue(o, null));
}
}
return res;
}
}
答案 7 :(得分:2)
基于MatíasFidemraizer的回答,这里有一个支持绑定除字符串以外的对象属性的版本。
using System.Collections.Generic;
using System.Linq;
using System.Reflection;
namespace WebOpsApi.Shared.Helpers
{
public static class MappingExtension
{
public static T ToObject<T>(this IDictionary<string, object> source)
where T : class, new()
{
var someObject = new T();
var someObjectType = someObject.GetType();
foreach (var item in source)
{
var key = char.ToUpper(item.Key[0]) + item.Key.Substring(1);
var targetProperty = someObjectType.GetProperty(key);
if (targetProperty.PropertyType == typeof (string))
{
targetProperty.SetValue(someObject, item.Value);
}
else
{
var parseMethod = targetProperty.PropertyType.GetMethod("TryParse",
BindingFlags.Public | BindingFlags.Static, null,
new[] {typeof (string), targetProperty.PropertyType.MakeByRefType()}, null);
if (parseMethod != null)
{
var parameters = new[] { item.Value, null };
var success = (bool)parseMethod.Invoke(null, parameters);
if (success)
{
targetProperty.SetValue(someObject, parameters[1]);
}
}
}
}
return someObject;
}
public static IDictionary<string, object> AsDictionary(this object source, BindingFlags bindingAttr = BindingFlags.DeclaredOnly | BindingFlags.Public | BindingFlags.Instance)
{
return source.GetType().GetProperties(bindingAttr).ToDictionary
(
propInfo => propInfo.Name,
propInfo => propInfo.GetValue(source, null)
);
}
}
}
答案 8 :(得分:0)
如果您使用的是Asp.Net MVC,请查看:
public static RouteValueDictionary AnonymousObjectToHtmlAttributes(object htmlAttributes);
这是System.Web.Mvc.HtmlHelper类上的静态公共方法。
答案 9 :(得分:0)
public Dictionary<string, object> ToDictionary<T>(string key, T value)
{
try
{
var payload = new Dictionary<string, object>
{
{ key, value }
};
} catch (Exception e)
{
return null;
}
}
public T FromDictionary<T>(Dictionary<string, object> payload, string key)
{
try
{
JObject jObject = (JObject) payload[key];
T t = jObject.ToObject<T>();
return (t);
}
catch(Exception e) {
return default(T);
}
}