Question

我对python很新，我想知道是否有人可以帮助我... 我正在尝试编写一个脚本来检查我的TS3服务器上是否有管理员。但是一整天后我都想不出来。

我使用的api链接在这里： http://py-ts3.readthedocs.io/en/latest/index.html

    import time
    import ts3


    def admincheck(nickname, id):
        while True:
            client = ts3conn.clientdbfind(pattern=nickname)
            group = ts3conn.servergroupclientlist(sgid=id)
            for client in client:
                print("client db id:\n" + (client["cldbid"]))
            for group in group:
                print("client db ids with admin:\n" + (group["cldbid"]))
                time.sleep(1.5)
            if int(client["cldbid"]) in range(int(group["cldbid"])):
                print("client has admin")
            else:
                print("client does not admin")



    with ts3.query.TS3Connection("localhost") as ts3conn:
            ts3conn.login(
                    client_login_name="serveradmin",
                    client_login_password="<ommited>"
            )
            ts3conn.use(sid=1)
            admincheck("test", "6")

我认为我的问题出在这一部分：

    if int(client["cldbid"]) in range(int(group["cldbid"])):
            print("client has admin")
        else:
            print("client does not admin")

如果有人可以提供帮助，那就太棒了:) 提前谢谢！

修改由于我没有说明手头的问题（noob here），这是一个示例输出：

    client db id:
    2
    client db ids with admin:
    2
    client db ids with admin:
    3
    client db ids with admin:
    4
    client does not admin

正如您所看到的，输出显示客户端没有admin，尽管客户端db id对应于列表中包含具有admin的ID的条目。

Answer 1

好读：couple of procedures

问题：

def admincheck(nickname, id):
    while True:
        client = ts3conn.clientdbfind(pattern=nickname)
        group = ts3conn.servergroupclientlist(sgid=id)

        # you are overwriting your client-list with its first element
        # both have the same name
        for client in client:
            print("client db id:\n" + (client["cldbid"]))

        # you are overwriting your group-list with its first element
        # both have the same name
        for group in group:
            print("client db ids with admin:\n" + (group["cldbid"]))
            time.sleep(1.5)

        # you should check if any client-id is equal to any inside group-ids
        # instead you do something with range - wich does not make much sense?
        if int(client["cldbid"]) in range(int(group["cldbid"])):
            print("client has admin")
        else:
            print("client does not admin")

如果您需要转换多个数字，请使用map：

text = [ "1","12","123","1234","12345"]
asInt = list( map(int,text))  # apply int() to each part of text, returns iterable 

print(asInt)  #   [1, 12, 123, 1234, 12345]

ids = ["5","7","1"] 
idNums = list(map(int,text))  # same 

print(any(x in asInt for x in idNums))   # checks if any x from idNums is 
                                         # inside asInt (your groupIds)

输出：

[1, 12, 123, 1234, 12345]
True

Doku：How to debug small programs和any()

在python

1 个答案: