Question

我在下面的查询中尝试将所有行放在最后一个Action =“UNLOCKED”之后，但看起来在子查询中不允许使用ORDER BY。

SELECT * 
FROM TABLE 
WHERE id >= (SELECT MAX(id) 
FROM TABLE  
WHERE ACTION='UNLOCKED' AND action_id=123 
ORDER BY CREATE_DATE DESC);

示例数据

Id action_id Action ... CREATE_DATE
1  123       ADD        03/18/2018
2  123       Unlocked   03/19/2018
3  123       Updated1   03/19/2018
4  123       Updated2   03/19/2018
5  123       Unlocked   03/20/2018
6  123       Updated3   03/20/2018
7  123       Updated4   03/20/2018

输出应为id为5,6,7的行。我应该用什么来获得这个输出

Answer 1

您可以在subselect上使用内部联接以获取max create_date

select * from TABLE 
INNER JOIN  (
select max(CREATE_DATE) max_date
from TABLE
where Action = 'Unlocked' ) T on t.max_date = TABLE.CREATE_DATE

Answer 2

您无需订购内部查询，因为它只返回一个值。您可以按照以下方式执行此操作

df <- structure(list(`0-5` = 700L, `5-10` = 1000L,  `10-15` = 1400L, `15-20` = 1700L, 
                     `20-25` = 1900L, `25-30` = 1500L, `30-35` = 1000L, `35-40` = 300L, 
                     `40-45` = 50L, `45-50` = 1L), .Names = c("0-5", "5-10",
                     "10-15", "15-20", "20-25", "25-30", "30-35", "35-40", "40-45", 
                     "45-50"), class = "data.frame", row.names = 1L)
df
  #   0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40 40-45 45-50
  # 1 700 1000  1400  1700  1900  1500  1000   300    50     1

使用oracle查找最近更新后的所有行

2 个答案: