Question

我正在尝试编写一个程序来检查圆圈是否包含另一个圆圈，如果某个圆圈位于圆圈内，或者我遇到问题，如果圆圈与另一个圆圈重叠。

import javafx.scene.shape.Circle;
public class Problem10_11 {
    public static void main(String[] args) {
        //Create circle with certain parameters.
        Circle2D c1 = new Circle2D(2, 2, 5.5);

        //Create output which will be tested by all our methods.
        System.out.println("The area for circle 1 is " +c1.getArea()+ 
                " and its perimeter is " + c1.getPerimeter());
        System.out.println("Is (3,3) contained within circle 1? " 
                + c1.contains(3, 3));
        System.out.println("Does circle 1 contain circle 2? " 
                + c1.contains(new Circle2D(4,5,10.5)));
        System.out.println("Does circle 1 overlap with circle 3? " 
                + c1.overlaps(new Circle2D(3, 5, 2.3)));
    }
}
class Circle2D {
    double x; //first parameter
    double y; //second parameter
    double radius; //third parameter

    Circle2D() {
    }
    public Circle2D(double x, double y, double radius) {
        this.x = x;
        this.y = y;
        this.radius = radius;
    }
    public void setX(double x) {
        this.x = x;  //set x
    }
    public double getX() {
        return x; //grab x
    }
    public void setY(double y) {
        this.y = y; //set y
    }
    public double getY() {
        return y; //grab y
    }
    public void setRadius(double radius) {
        this.radius = radius; //set radius
    }
    public double getRadius() {
        return radius; //grab radius
    }
    public double getArea() {
            double area = Math.PI*radius*radius; //formula for area
                return area;
    }
    public double getPerimeter() {
            double perimeter = 2*Math.PI*radius; //formula for perimeter
                return perimeter;
    }
    public boolean contains(double x, double y) {
        //Use distance formula to check if a specific point is within our circle. 
            double distance = Math.sqrt(Math.pow(this.x - x, 2) + (Math.pow(this.y - y, 2)));
            if (distance  <= radius * 2)
                return true;
            else {
                return false;
            }
    }
    public boolean contains(Circle2D circle) {
        //Use distance formula to check if a circle is contained within another circle.
        double distance = Math.sqrt(Math.pow(circle.getX() - x, 2) + (Math.pow(circle.getY() - y, 2)));
        if (distance <= (this.radius - circle.radius)) {
            return true;
        } else {
            return false;
        }
    }
    public boolean overlaps(Circle2D circle) {
        //Use distance formula to check if a circle overlaps with another circle.
            double distance = Math.sqrt(Math.pow(circle.getX() - x, 2) + (Math.pow(circle.getY() - y, 2)));



    }
}

所以我的重叠方法一直在底部，但我内心没有任何东西，因为我不确定该做什么。我试过这个：

if (distance <= radius) return true;
        else return false;

但是没有用。所以我不确定还有什么可以尝试的。仅供参考，我正在尝试检查c1是否与带参数的圆重叠（3,5,2.3）。我感谢任何建议/意见。

Answer 1

如果圆心之间的距离小于两个圆的半径之和，那么它们就会重叠。

double minDistance = Math.max(circle.getRadius(),this.radius) - Math.min(circle.getRadius(),this.radius);
    if (distance <= (this.radius + circle.getRadius()) && distance>= minDistance) return true;
            else return false;

Answer 2

1.-你必须将两个圆圈放在太空中，给他们一些坐标 2.-你必须得到2个圆圈的向量 3.-你必须normailze这些向量并获得正确的距离，单位，我要使用像素 4.-最后你必须检查这两个矢量之间的距离是否小于两个圆的辐射，如果是，那么它们是重叠的。
在这里你有一个更好的解释链接： https://gamedevelopment.tutsplus.com/tutorials/when-worlds-collide-simulating-circle-circle-collisions--gamedev-769，当我们想要检查圆圈碰撞时（对于2D游戏），这是我们在游戏开发中常用的东西

Answer 3

您可以参考Relative position of two circles。

public boolean overlaps(Circle2D circle) {
        //Use distance formula to check if a circle overlaps with another circle.
        double distance = Math.sqrt(Math.pow(circle.getX() - x, 2) + (Math.pow(circle.getY() - y, 2)));
        return distance <= (this.radius + circle.radius) and distance >= Math.abs(this.radius - circle.radius)
}

如何检查圆圈是否重叠

3 个答案: