Question

所以我试图创建的程序是Craps的游戏，我试图看看程序是否重复，因为我真的不知道如何使用递归方法，教授过去了不久前。我想知道它是否正常运行，但是当我运行它时得到：＆＃34;线程中的异常＆＃34; main＆＃34; Main.rollDice（Main.java:29）Main.rollDice（Main.java:25）java.util.Random。（Unknown Source）的java.lang.StackOverflowError和Main.java:29重复多次。我是编码的新手，我的教授并不是最好的。请在12小时内提供帮助！

import java.util.*;

public class Main {
static int die1 = 0, die2 = 0, dieSum = 0, balance = 0, bet = 0;
public static void main(String[] args) {
    Scanner kbd = new Scanner(System.in);
    Random gen = new Random();

    System.out.println("Welcome to the game of Craps!");
    System.out.println("Every round you will make a wager with dollars only.");
    System.out.println("The minimum wager is $10.");
    System.out.println("You can continue to play as long as you have enough money to cover the minimu wager.");
    System.out.println("You can cash out at the end of any round if you would like.");

    balance = gen.nextInt(1000)+50;
    System.out.println("Your starting balance is: $" + balance);
    int i = 0;
    if ((rollDice()<=2)||(i==5)) {
        System.out.println(rollDice());
        i = i++;
    }
}
public static int rollDice() {
    Random gen = new Random();
    die1 = gen.nextInt(6)+1;
    die2 = gen.nextInt(6)+1;
    dieSum = die1 + die2;
    return rollDice();
}
// TODO Auto-generated method stub

}

Answer 1

您的rollDice方法以无条件的方式递归调用自身。此行返回调用rollDice return rollDice();的结果。每个递归调用都会添加到执行堆栈中。一旦堆栈“空间不足”，就会抛出堆栈溢出异常。我怀疑你打算像这样

返回dieSum

public static int rollDice() {
    Random gen = new Random();
    die1 = gen.nextInt(6)+1;
    die2 = gen.nextInt(6)+1;
    dieSum = die1 + die2;    
    return dieSum;
}

为什么我的程序没有运行？

1 个答案: