Question

当我尝试从get路由获取数据时，如果我只返回响应，则会获取数据。但是当我使用mongoose方法时，即mongoose.methods.summary = function（）{...}。

这是代码（此代码转到catch块并始终返回错误）：

router.get('/callsheets', authenticate, (req, res) => {
  Callsheet.find(req.query)
    .then(callsheets => res.send(callsheets.summary()))
    .catch(err => res.json({ err }));
});
//the query is {creator: id}, which is passed from axios
//no errors in passing the query

以下是我的猫鼬模型的代码：从'mongoose'进口猫鼬;

const callSheetSchema = new mongoose.Schema({
  creator: { type: String, default: '' },
  published: { type: Boolean, default: false },
  sent: { type: Boolean, default: false },
  completed: { type: Boolean, default: false },
  archived: { type: Boolean, default: false },
  client: { type: String, default: '' },
  project: { type: String, default: '' },
  production: { type: Array, default: [] },
  wardrobe: { type: Array, default: [] }
});

callSheetSchema.methods.summary = function() {
  const summary = {
    id: this._id,
    creator: this.creator,
    published: this.published,
    sent: this.sent,
    completed: this.completed,
    archived: this.archived,
    client: this.client,
    project: this.project,
    production: this.production,
    wardrobe: this.wardrobe
  };
  return summary;
};

export default mongoose.model('callsheet', callSheetSchema);

同样，如果我只返回res.send(callsheet)，则会正确发送数据。如果我返回res.send(callsheet.summary())，我会点击错误块。

非常感谢任何帮助。

Answer 1

尝试使用虚拟财产http://mongoosejs.com/docs/guide.html#virtuals

callSheetSchema.virtual('summary').get(function () {
  const summary = {
    id: this._id,
    creator: this.creator,
    published: this.published,
    sent: this.sent,
    completed: this.completed,
    archived: this.archived,
    client: this.client,
    project: this.project,
    production: this.production,
    wardrobe: this.wardrobe
  };
  return summary;
});

然后将其用作

router.get('/callsheets', authenticate, (req, res) => {
  Callsheet.find(req.query)
    .then(callsheets => res.send(callsheets.summary)) // <- not a method
    .catch(err => res.json({ err }));
});

Answer 2

尝试以这种方式导出 module.exports = callSheetSchema代替export default callSheetSchema

Answer 3

在节点上，我使用module.export而不是export default

当我使用方法返回数据时，mongoose.find（req.query）导致错误

3 个答案: