处理将图像上传到AWS实例的要求。 UI和服务是分开的,并通过REST连接。服务在nodejs中。从UI我们正在对后端服务进行ajax调用,以将图像上传到AWS。
问题: 当我通过POSTMAN请求上传图像时,我可以看到上传的响应与在AWS中正确上传的文件一起上传。 而当我通过AJAX调用上传图像时,我在浏览器中没有响应,并且图像也没有上传到aws中。
以下是ajax中的代码:
var formData = new FormData();
formData.append('image', $('#tx_file_programa')[0]);
$.ajax({
method: 'POST',
type: "POST",
url: 'http://10.0.0.95:9999/photo/1',
contentType: false,
processData: false,
async: false,
cache: false,
beforeSend: function (xhr) {
xhr.setRequestHeader('Authorization', 'Bearer ' + access_token );
},
data: formData,
success: function (data) {
console.log('response from server is : ', data);
}
//dataType: 'json'
});
这是后端服务。
server.post('/photo/:count', function (req, res) {
if (req.getContentType() == 'multipart/form-data') {
var form = new formidable.IncomingForm(),
files = [], fields = [];
var result = [];
var noOfFiles = req.params.count;
var count = 0;
console.log('noOfFiles', noOfFiles);
form.on('field', function(field, value) {
fields.push([field, value]);
console.log(fields);
})
form.on('progress', function(bytesReceived, bytesExpected) {
console.log('err');
});
form.on('error', function(err) {
console.log('err',err);
});
form.on('aborted', function() {
console.log('aborted', arguments);
});
new Promise(function(resolve, reject) {
var result = [];
form.onPart = function (part) {
var data = null;
const params = {
Bucket: 'xxxxx',
Key: uuidv4() + part.filename,
ACL: 'public-read'
};
var upload = s3Stream.upload(params);
upload.on('error', function (error) {
console.log('errr', error);
});
upload.on('part', function (details) {
console.log('part', details);
});
upload.on('uploaded', function (details) {
let extension = details.Location.split('.');
if(['JPG', 'PNG'].indexOf(extension[extension.length - 1].toUpperCase()) > -1) {
var ext = extension[extension.length - 1];
count++;
result.push(details.Location);
if(count == noOfFiles) {
resolve(result);
}
}
});
part.pipe(upload);
}
}).then(function(result){
console.log('end', result);
res.writeHead(200, {'content-type': 'text/plain'});
res.end('received files:\n\n ' + util.inspect(result));
})
form.parse(req, function (err, fields, files) {
})
return;
} else {
BadRequestResponse(res, "Invalid request type!");
}
})
答案 0 :(得分:1)
@ user3336194,你能用这个来检查,这是不可行的
var appIconFormData = null
$(":file").change(function () {
var file = this.files[0], name = file.name, size = file.size, type = file.type;
var imageType = new Array("image/png", "image/jpeg", "image/gif", "image/bmp");
if (jQuery.inArray(type, imageType) == -1) {
return false;
} else {
appIconFormData = new FormData();
appIconFormData.append('appimage', $('input[type=file]')[0].files[0]);
}
});
$.ajax({
url: 'your/api/destination/url',
type: 'POST',
data: appIconFormData,
cache: false,
contentType: false,
processData: false,
success: function (data) {
console.log(data)
},
error: function (e) {
}
});
答案 1 :(得分:0)
我认为你发送formdata的方式不正确。
尝试以下两种方式:
您可以将整个表单提供给FormData()进行处理
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
或指定FormData()
的确切数据var formData = new FormData();
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);