我正在制作像优步这样的出租车预订应用 用户拖动地图以使用引脚选择他的位置
我抓住那个引脚的LatLng。
这是我的代码:
public void onMapReady(GoogleMap googleMap) {
mMap = googleMap;
mMap.setMapType(GoogleMap.MAP_TYPE_NORMAL);
mMap.setOnCameraIdleListener(new GoogleMap.OnCameraIdleListener() {
@Override
public void onCameraIdle() {
pinLocation = mMap.getCameraPosition().target;
setPickupLocationPrefs(pinLocation);
}
});
//Initialize Google Play Services
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (ContextCompat.checkSelfPermission(this,
Manifest.permission.ACCESS_FINE_LOCATION)
== PackageManager.PERMISSION_GRANTED) {
buildGoogleApiClient();
updateLocationUI();
}
}
else {
buildGoogleApiClient();
updateLocationUI();
}
}
如果应用程序在该位置运行,我希望获取该引脚的地址以向我的用户显示(例如优步)。
如何从引脚位置坐标获取该地址?
答案 0 :(得分:2)
使用反向地理编码。首先从引脚点获取纬度和经度。更好地在后台线程中处理这个问题。否则会阻止用户界面。
describe
修复UI阻止的解决方案
使用线程和处理程序的完整示例代码,可在不阻止UI的情况下获取public sessionId;
constructor(){
var socket = io.connect('http://**.***.***.***:****');
socket.on('connect', function (data) {
console.log('user connected');
socket.emit('add user', { userId: uid });
});
socket.on('create channel', function (data) {
console.log(data);
this.sessionId = data.sessionId; //error
this.function(); //error
socket.emit('feedback', { received: true });
});
}
function(){}
答案。
Geocoder调用程序,可以位于Helper类
中double latitude = location.getLatitude();
double longitude = location.getLongitude();
Geocoder gc = new Geocoder(this, Locale.getDefault());
try {
List<Address> addresses = gc.getFromLocation(lat, lng, 1);
StringBuilder sb = new StringBuilder();
if (addresses.size() > 0) {
Address address = addresses.get(0);
for (int i = 0; i < address.getMaxAddressLineIndex(); i++)
sb.append(address.getAddressLine(i)).append("\n");
sb.append(address.getLocality()).append("\n");
sb.append(address.getPostalCode()).append("\n");
sb.append(address.getCountryName());
}
String Address=sb.toString());
}catch(Exception E);
以下是您在用户界面Geocoder
中对此地理编码程序的调用:
public static void getAddressFromLocation(
final Location location, final Context context, final Handler handler) {
Thread thread = new Thread() {
@Override public void run() {
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
String result = null;
try {
List<Address> list = geocoder.getFromLocation(
location.getLatitude(), location.getLongitude(), 1);
if (list != null && list.size() > 0) {
Address address = list.get(0);
// sending back first address line and locality
result = address.getAddressLine(0) + ", " + address.getLocality();
}
} catch (IOException e) {
Log.e(TAG, "Impossible to connect to Geocoder", e);
} finally {
Message msg = Message.obtain();
msg.setTarget(handler);
if (result != null) {
msg.what = 1;
Bundle bundle = new Bundle();
bundle.putString("address", result);
msg.setData(bundle);
} else
msg.what = 0;
msg.sendToTarget();
}
}
};
thread.start();
}
Activity/Fragment
中的处理程序类在您的用户界面中显示结果:
getAddressFromLocation(PinPointLocation, mContext, new GeocoderHandler());