Question

我将地图初始化为：

var map = new Map();

当我console.log(map)时，我得到：

testCreateBadAppointmentRequest: 
   { name: 'testCreateBadAppointmentRequest',
     time: 0.02926,
     status: 'Passed' },
  testAppointmentRequestAPI: 
   { name: 'testAppointmentRequestAPI',
     time: 0.051030000000000006,
     status: 'Passed' },

我想在值的时间属性上对此地图进行排序。我如何在nodejs中做到这一点？是否有现成的排序功能？

Answer 1

您需要先将Map转换为Array，然后使用内置sort并提供回调：

const sorted = Array.from(map).sort(function(a, b) {
    if (a.time < b.time) return -1;
    if (a.time > b.time) return 1;
    return 0;
});

Answer 2

Map订单由广告订单决定。

应该注意的是，作为对象地图的地图，尤其是字典字典，只会映射到对象的插入顺序 - 这是随机的而不是有序的。

使用Array.from或使用地图上的spread operator可迭代将地图转换为数组。然后对数组进行排序：

const map = new Map()
map.set('testCreateBadAppointmentRequest', { name: 'testCreateBadAppointmentRequest', time: 0.02926, status: 'Passed' });
map.set('testAppointmentRequestAPI', { name: 'testAppointmentRequestAPI', time: 0.051030000000000006,  status: 'Passed' });

// convert map to array
console.log('array', [...map.entries()]);
const array = Array.from(map);

// sort (inverse sort to change your current sort)
array.sort((x, y) => y[1].time - x[1].time);
console.log('sorted', array);

// create new map with objects pairs in the desired order:
const timeSortedMap = new Map(array);
console.log('sorted map', [...timeSortedMap]);

Answer 3

您必须创建一个新的Map对象，因为Map对象按插入顺序迭代其元素。

＆＃13;

    const inputMap = new Map(
      [
        ['testCreateBadAppointmentRequest',
          {
            name: 'testCreateBadAppointmentRequest',
            time: 0.02926,
            status: 'Passed'
          }
        ],
        ['testAppointmentRequestAPI',
          {
            name: 'testAppointmentRequestAPI',
            time: 0.051030000000000006,
            status: 'Passed'
          },
        ],
        ['another',
          {
            name: 'name',
            time: 0.0001,
            status: 'Passed'
          },
        ]
      ]);

    const sortedMap = new Map([...inputMap.entries()].sort((entryA, entryB) => entryB[1].time - entryA[1].time));
for (const value of sortedMap.values()) {
  console.log(value)
}

＆＃13;

对map进行排序，其中value是具有多个值的对象

3 个答案: