Question

我配置了一个连接到Oracle Service Cloud的REST API POST请求，它以下面的json格式接收响应：

{"count":16,"name":"Report Name","columnNames":["Connection","Complete Name","Login ID","Login Time","Logout Time","IP Direction"],"rows":[["PGALICHI","Robert The IT Guy","3205","2018-01-25 08:52:23","2018-01-25 15:00:50","201.255.56.151"],["PGALICHI","Lucas The other IT Guy","3204","2018-01-25 08:52:21","2018-01-25 15:00:51","201.255.56.151"]],"links":[{"rel":"self","href":"https://web--tst1.custhelp.com/services/rest/connect/v1.4/analyticsReportResults"},{"rel":"canonical","href":"https://web--tst1.custhelp.com/services/rest/connect/v1.4/analyticsReportResults"},{"rel":"describedby","href":"https://web--tst1.custhelp.com/services/rest/connect/v1.4/metadata-catalog/analyticsReportResults","mediaType":"application/schema+json"}]}

此信息将是仅打印行的脚本的输入，我现在需要的是，首先按“登录时间”排序所有行，然后使用“登录时间”筛选所有值“等于或早于具有最后”登录时间“值的变量。

这是我现在用来获取行的代码示例：

class OracleORNHandler:

def __init__(self,**args):
    pass

def __call__(self, response_object,raw_response_output,response_type,req_args,endpoint):
    if response_type == "json":        
        output = json.loads(raw_response_output)
        for row in output["rows"]:
            print_xml_stream(json.dumps(row))                      
    else:
        print_xml_stream(raw_response_output)

Answer 1

这需要更多编码。但是我会解释逻辑方法。您可能希望稍微改变编码方法。

将字符串加载到字典中。

固定字符串

json_out = '{"count":16,"name":"Report Name","columnNames":["Connection","Complete Name","Login ID","Login Time","Logout Time","IP Direction"],"rows":[["PGALICHI","Robert The IT Guy","3205","2018-01-25 08:52:23","2018-01-25 15:00:50","201.255.56.151"],["PGALICHI","Lucas The other IT Guy","3204","2018-01-25 08:52:21","2018-01-25 15:00:51","201.255.56.151"]],"links":[{"rel":"self","href":"https://web--tst1.custhelp.com/services/rest/connect/v1.4/analyticsReportResults"},{"rel":"canonical","href":"https://web--tst1.custhelp.com/services/rest/connect/v1.4/analyticsReportResults"},{"rel":"describedby","href":"https://web--tst1.custhelp.com/services/rest/connect/v1.4/metadata-catalog/analyticsReportResults","mediaType":"application/schema+json"}]}'

dic_json = json.loads(json_out)

将rows转换为词典

登录时间用作值，因为我们将需要它以便稍后进行排序。

使用datetime将字符串转换为日期

from datetime import datetime
rows_list = dic_json['rows']
d = dict()

for x in rows_list:
    datetime_object = datetime.strptime(x[4], '%Y-%m-%d %H:%M:%S')
    d[x.__str__()] = datetime_object

注意：由于登录时间可能是唯一的，我选择整个列表作为密钥即使不确定登录ID在这里是唯一的。

使用collections.OrderedDict按时排序。;

即

import collections
# sort by time i.e dictionary values
od2 =collections.OrderedDict(sorted(d.items(), key=lambda t: t[1]))

根据日期时间条件过滤值。

<强> Input_time date_time_req = datetime.strptime('2018-01-25 08:52:23', '%Y-%m-%d %H:%M:%S')

for y in od2.keys():
    if od2[y] <= date_time_req:
        print(y)

此输出为字符串，您可以修剪并将其转换回列表。

如何使用python的行值来过滤REST API行响应？

1 个答案: