Question

我正在以

格式从网页的html中提取列表

lst = '["a","b","c"]' # (type <str>)

上面的数据类型是 str ，我希望它转换为python 列表类型，这样的事情

lst = ["a","b","c"]  #(type <list>)

我可以通过

获得上述内容

lst = lst[1:-1].replace('"','').split(',')

但由于a，b＆amp; c的实际值非常长且复杂（包含长html文本），我无法依赖上述方法。

我也试过用json模块并使用json.loads(lst)，这给出了以下异常

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/json/__init__.py", line 339, in loads
    return _default_decoder.decode(s)
  File "/usr/local/lib/python2.7/json/decoder.py", line 364, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/local/lib/python2.7/json/decoder.py", line 382, in raw_decode
    raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded

在Python中以任何方式转换为列表？

编辑：列表的实际值是： ['reqlistitem.no','reqlistitem.applyonlinejobdesc','reqlistitem.no','reqlistitem.referjobdesc','reqlistitem.applyemailsubjectapplication','reqlistitem.applyemailjobdesc','reqlistitem.no','reqlistitem.addedtojobcart','reqlistitem.displayjobcartactionjobdesc','reqlistitem.shareURL','reqlistitem.title','reqlistitem.shareable','reqlistitem.title','reqlistitem.contestnumber','reqlistitem.contestnumber','reqlistitem.description','reqlistitem.description','reqlistitem.primarylocation','reqlistitem.primarylocation','reqlistitem.otherlocations','reqlistitem.jobschedule','reqlistitem.jobschedule','reqlistitem.jobfield','reqlistitem.jobfield','reqlistitem.displayreferfriendaction','reqlistitem.no','reqlistitem.no','reqlistitem.applyonlinejobdesc','reqlistitem.no','reqlistitem.referjobdesc','reqlistitem.applyemailsubjectapplication','reqlistitem.applyemailjobdesc','reqlistitem.no','reqlistitem.addedtojobcart','reqlistitem.displayjobcartactionjobdesc','reqlistitem.shareURL','reqlistitem.title','reqlistitem.shareable']

Answer 1

我认为您正在寻找literal_eval：

import ast

string = '["a","b","c"]'

print ast.literal_eval(string) # ['a', 'b', 'c']

Answer 2

示例字符串中的问题是单引号。 JSON标准需要双引号。

如果您将单引号更改为双引号，它将起作用。一种简单的方法是使用str.replace()：

import json
s = "['reqlistitem.no','reqlistitem.applyonlinejobdesc','reqlistitem.no']"
json.loads(s.replace("'", '"'))
#[u'reqlistitem.no', u'reqlistitem.applyonlinejobdesc', u'reqlistitem.no']

如何将列表类型更改为str？

2 个答案: