空手道测试框架中的重试机制

Question

空手道测试框架中的重试机制如何在空手道测试框架（如Junit和TestNG）中重试失败测试。 就像是 公共类重试实现IRetryAnalyzer {

private int count = 0;
private static int maxTry = 3;

@Override
public boolean retry(ITestResult iTestResult) {
    if (!iTestResult.isSuccess()) {                      //Check if test not succeed
        if (count < maxTry) {                            //Check if maxtry count is reached
            count++;                                     //Increase the maxTry count by 1
            iTestResult.setStatus(ITestResult.FAILURE);  //Mark test as failed
            return true;                                 //Tells TestNG to re-run the test
        } else {
            iTestResult.setStatus(ITestResult.FAILURE);  //If maxCount reached,test marked as failed
        }
    } else {
        iTestResult.setStatus(ITestResult.SUCCESS);      //If test passes, TestNG marks it as passed
    }
    return false;
}

}

Answer 1

它在版本 0.9.5.RC 5上对我有效。但是，也许这是前面提到的“解决方法”之一？

您要做的就是这样，默认尝试3次：

const divInput = document.getElementById('divInput');
const textarea = document.getElementById('inputTypePreview');

divInput.addEventListener('input', (event) => {
  const t = event.inputType;
  textarea.innerHTML = `${t} \n`;
  if (t === 'insertParagraph' || t === 'insertLineBreak') 
    textarea.innerHTML = 'Enter detected \n';
 });

Answer 2

截至目前，这是一项开放式功能请求：https://github.com/intuit/karate/issues/247

但是有很多工作要做。如果查看轮询示例，您可能会得到一些想法：https://github.com/intuit/karate/blob/master/karate-demo/src/test/java/demo/polling/polling.feature