Question

我有2个文本文件，我想比较一个与另一个的内容。需要检查Unique.txt中的ip是否存在于CheckIp.txt中。我的代码如下：

with open("/root/nix_bsd_mac_inventory-master/Unique.txt") as fp:
    for line in fp:
        print(line)
        with open("/root/nix_bsd_mac_inventory-master/CheckIp.txt") as fp1:
            for line1 in fp1:
                line1 = line1.rstrip()
                if line == line1:
                    print (line1 + "Ip is Already Present")
                else:
                    print ("Processing Ip:"+ line)

看来我做错了。有人可以帮助我吗？

Answer 1

也许您还应rstrip() Unique.txt中CheckIp.txt的行，与Unique.txt一样，删除新行和其他杂散尾随空格。这可能会解决它。

不是为Unique.txt中的每一行打开第二个文件，而是将第二个文件读入一个集合，然后将with open('/root/nix_bsd_mac_inventory-master/CheckIp.txt') as f: ips = set(line.rstrip() for line in f) with open('/root/nix_bsd_mac_inventory-master/Unique.txt') as f: for line in f: line = line.rstrip() if line in ips: print('{}: Ip is Already Present'.format(line)) else: print('Processing Ip: {}'.format(line))中的行与集合中的行进行比较：

REGEXP

Answer 2

此代码应该适合您：正在检查Unique.txt中是否找到了CheckIp的内容。

with open("Unique.txt") as firstFile:
    checkIP = firstFile.read().strip()

with open("CheckIp.txt") as secondFile:
    contents = secondFile.read().strip()

if checkIP in contents:
    print ("{} IP is Already Present".format(checkIP))

else:
    print ("Processing Ip: {}".format(checkIP))

但是，如果两个文件只包含您要比较的IP，那么您可以进行更具体的检查：

if checkIP == contents:
    print ("{} IP is Already Present".format(checkIP))

else:
    print ("Processing Ip: {}".format(checkIP))

Answer 3

考虑您的文件＆＃34; Unique.txt＆＃34; 只是会包含您正在寻找的IP：

f1 = open('CheckIp.txt', 'r')
data= ''.join(f1.readlines())
f2 = open('Unique.txt','r')
toFind = f2.readline()
if data.find(toFind) != -1:
    print("ip "+toFind+" found!")
else:
    print("ip "+toFind+" not found!")

比较python中的两个文件内容

3 个答案: