按sql server按组列出值

Question

我有一张表格如下

TextBlock

如何编写SQL查询以使所有PriceCardId具有Day包含

Id | PriceCardId | Days
1  |   1         | 2
2  |   1         | 4
3  |   1         | 5
4  |   1         | 6
5  |   1         | 3
6  |   2         | 5
7  |   2         | 3
8  |   3         | 6

谢谢！

Answer 1

我想你想要：

select pricecardid
from t
where day in (2, 4, 5, 6)
group by pricecardid
having count(*) = 4;  -- the number of days you are looking for

这假设您的表中没有重复项。如果存在重复项，请使用having count(distinct day)代替count(*)。

注意：您可以将其标记为：

with d as (
      select v.dy
      from values ( (2), (4), (5), (6) ) v(dy)
     )
select pricecardid
from t 
where day in (select d.dy from d)
group by pricecardid
having count(*) = (select count(*) from d);

Answer 2

试试这个：

SELECT PriceCardId 
FROM [My_Table] 
WHERE [Day] IN(2,4,5,6)
GROUP BY PriceCardId
HAVING COUNT(DISTINCT [Day])=4