以下代码使用单个屏幕MainScreen
创建Kivy应用,并显示Label
和TextInput
对象。
如果您在应用首次加载时提供一些键盘输入,它会在控制台中打印有关按下了哪个键的信息。但是,如果您再单击TextInput
对象,键盘将重新聚焦,以便您可以键入TextInput
对象。但是,一旦您单击TextInput
对象,例如,在标签或背景上,按下更多键,相同的控制台打印操作不会执行;看起来键盘并没有散焦'来自TextInput
对象。
单击TextInput
对象后,如何重新获得键盘焦点?
from kivy.app import App
from kivy.lang import Builder
from kivy.core.window import Window
from kivy.uix.screenmanager import Screen, ScreenManager
from kivy.uix.textinput import TextInput
kv = '''ScreenManagement:
MainScreen:
<MainScreen>:
name: "main"
BoxLayout:
Label:
text: "Label"
font_size: 20
size_hint: 0.2,0.1
TextInput
input_filter: 'float'
font_size: 20
hint_text: "Input Text"
size_hint: 0.2,0.1'''
class MainScreen(Screen):
def __init__(self, **kwargs):
super().__init__(**kwargs)
self._keyboard = Window.request_keyboard(self._keyboard_closed, self)
self._keyboard.bind(on_key_down=self._on_keyboard_down)
def _keyboard_closed(self):
self._keyboard.unbind(on_key_down=self._on_keyboard_down)
self._keyboard = None
def _on_keyboard_down(self, keyboard, keycode, text, modifiers):
print('INFO: The key', keycode, 'has been pressed')
return True # return True to accept the key. Otherwise, it will be used by the system.
class ScreenManagement(ScreenManager):
pass
class MainApp(App):
def build(self):
return Builder.load_string(kv)
if __name__ == "__main__":
MainApp().run()
答案 0 :(得分:1)
一种可能的解决方案是使用on_touch_down
事件,并在按下不包含TextInput
的部分时重新配置键盘:
class MainScreen(Screen):
def __init__(self, **kwargs):
super().__init__(**kwargs)
self.config_keyboard()
def on_touch_down(self, touch):
self.isTextInput = False
def filter(widget):
for child in widget.children:
filter(child)
if isinstance(widget, TextInput) and widget.collide_point(*touch.pos):
self.isTextInput = True
widget.on_touch_down(touch)
filter(self)
if not self.isTextInput and self._keyboard is None:
self.config_keyboard()
def config_keyboard(self):
self._keyboard = Window.request_keyboard(self._keyboard_closed, self)
self._keyboard.bind(on_key_down=self._on_keyboard_down)
def _keyboard_closed(self):
self._keyboard.unbind(on_key_down=self._on_keyboard_down)
self._keyboard = None
def _on_keyboard_down(self, keyboard, keycode, text, modifiers):
print('INFO: The key', keycode, 'has been pressed')
return True # return True to accept the key. Otherwise, it will be used by the system.