Learning_tutors:
Learning_subject:
Learning_subjects:
Learning_level:
Learning_level table
我希望能够根据学习科目表中的subjectID获取教导科目的导师的名字,并将其加入学习科目表,该表格对应于学习中的tutorID导师表
这是我尝试过的
SELECT learning_subjects.levelid,
learning_subjects.tutorid,
learning_tutor.id,
learning_tutor.NAME,
learning_level.id
FROM learning_subjects
INNER JOIN learning_level
ON learning_subjects.levelid = learning_level.id
INNER JOIN learning_subjects.tutorid
ON learning_tutor.id
WHERE learning_subjects.tutorid = 1
答案 0 :(得分:-1)
select
s.levelID, t.Name, l.Subject
from
Learning_tutors t, Learning_subject l, Learning_subjects s
where s.tutorID = t.ID AND s.subjectID = l.ID
这为您提供了一种从各种表格中获取信息的灵活方式。
答案 1 :(得分:-1)
我认为你的第二次加入稍微偏离了
SELECT learning_subjects.levelid,
learning_subjects.tutorid,
learning_tutor.id,
learning_tutor.NAME,
learning_level.id
FROM learning_subjects
INNER JOIN learning_level
ON learning_subjects.levelid = learning_level.id
**INNER JOIN learning_tutors
ON learning_tutor.id = learning_subjects.tutorid**
WHERE learning_subjects.tutorid = 1
答案 2 :(得分:-1)
您需要在 INNER JOIN 和 WHERE 子句部分略有变化:
FROM learning_subjects INNER JOIN learning_level ON learning_subjects.levelid = learning_level.id
INNER JOIN learning_tutor ON learning_subjects.tutorid = learning_tutor.id
WHERE learning_subjects.subjectID = 1