SQL - 将案例语句与动态表一起使用(未知行数)

时间:2018-03-21 00:16:13

标签: mysql sql stored-procedures case

我在尝试创建存储过程时遇到了一些问题。我有2个表,eTaskseStaff。以下是每个表的列:

eTasks

TaskID | StaffID | Title | CreateDate

eStaff

StaffID | Name

目前,正如数据所示,所有任务都分配给StaffID'1'。 eTaskseStaff表都使用新任务和工作人员更新,或者它们被取出,这些表每天都不会有相同的行。有些日子,eTask表中会有1000行,而下一行可能只有400行。有些日子,eStaff表中会有3名工作人员,下一天可能会有12名。< / p>

我想要做的是在运行存储过程时在当前StaffID之间均匀分配任务。

到目前为止,这就是我所拥有的:

CREATE PROCEDURE UpdatingeTasksTable 
AS
    DECLARE t_rowCount INTEGER
    DECLARE s_staffIDCount INTEGER

    SET t_rowCount = SELECT COUNT(*) FROM eTasks
    SET s_staffIDCount = SELECT DISTINCT StaffID FROM eStaff

    UPDATE eTasks
    SET StaffID = CASE 
                     WHEN TaskID % t_rowCount = 1 THEN 1
                     WHEN TaskID % t_rowCount = 2 THEN 4
                     WHEN TaskID % t_rowCount = 3 THEN 3
                     WHEN TaskID % t_rowCount = 4 THEN 2
                  END
    FROM eTasks b
    WHERE TaskID = b.TaskID;

我知道,我的查询目前是什么,它只会将任务分成4个人。有没有办法使CASE语句动态化,这样就不会有一组静态数字?

2 个答案:

答案 0 :(得分:0)

这在MySQL中有点困难。您可以通过添加行号列来编写查询来执行此操作:

select et.*, s.staffId
from (select count(*) as cnt
      from staff
     ) ss cross join
     (select et.*, (@rne := @rne + 1) as rn
      from etasks et cross join
           (select @rne := 0) params
     ) et join
     (select s.*, (@rns := @rns + 1) as rn
      from staff s cross join
           (select @rns := 0) params
     ) s
     on s.rn = mod(et.rn, ss.cnt) + 1;

然后,您可以使用update

将其加入join
update etask et join
       (select et.*, s.staffId
        from (select count(*) as cnt
              from staff
             ) ss cross join
             (select et.*, (@rne := @rne + 1) as rn
              from etasks et cross join
                   (select @rne := 0) params
             ) et join
             (select s.*, (@rns := @rns + 1) as rn
              from staff s cross join
                   (select @rns := 0) params
             ) s
             on s.rn = mod(et.rn, ss.cnt) + 1
       ) ets
       on et.taskid = ets.taskid
    set et.staffid = ets.staffid;

答案 1 :(得分:0)

我得到了这个测试。我没有使用存储过程,我只是在MySQL会话中使用用户定义的变量。但是同样的想法也适用于本地存储的proc变量。

mysql> select count(*) into @staffcount from estaff; -- in my test this is 4

mysql> set @staffid = 0;
mysql> update etasks set staffid = (@staffid := (@staffid+1)%@staffcount)+1;

mysql> select * from etasks;
+--------+---------+-------+------------+
| taskid | staffid | title | createdate |
+--------+---------+-------+------------+
|      1 |       2 | NULL  | NULL       |
|      2 |       3 | NULL  | NULL       |
|      3 |       4 | NULL  | NULL       |
|      4 |       1 | NULL  | NULL       |
|      5 |       2 | NULL  | NULL       |
|      6 |       3 | NULL  | NULL       |
|      7 |       4 | NULL  | NULL       |
|      8 |       1 | NULL  | NULL       |
|      9 |       2 | NULL  | NULL       |
|     10 |       3 | NULL  | NULL       |
|     11 |       4 | NULL  | NULL       |
|     12 |       1 | NULL  | NULL       |
|     13 |       2 | NULL  | NULL       |
|     14 |       3 | NULL  | NULL       |
|     15 |       4 | NULL  | NULL       |
|     16 |       1 | NULL  | NULL       |
|     17 |       2 | NULL  | NULL       |
|     18 |       3 | NULL  | NULL       |
+--------+---------+-------+------------+

这确实假设您的staffid值从1到estaff中的行数。如果你想将值1到4映射到estaff中的相应行,并分配staffid,那么这是一个解决方案:

mysql> update etasks as t, 
    (select staffid, @rownum:=@rownum+1 AS rownum 
     from (select @rownum:=0) AS _init cross join estaff) as s 
  set t.staffid = s.staffid 
  where s.rownum = (@staffid := (@staffid+1)%@staffcount)+1;