Question

我有这个简单的SQL Select查询：

SELECT part_number, bin_location FROM list ORDER BY bin_location

这会给我一个这样的结果：

part_number       bin_location
Alaska wine           A1
German water          A2
London whisky         A3
German wine           A4
London water          B1
German wine           B2
London whisky         B3
German wine           C1
London whisky         C2
Water Green Wine      C3
Pure Water            D1
Orange whisky         D2
Ireland Moat          D3
French wine           XX
Italy water           XX
Water Green Wine      XX
Pure Water            XX
Orange whisky         XX
Ireland Moat          XX
French wine           XX
Italy water           XX

现在我要做的是按bin_location排序，一旦bin_location等于xx order by part_number。

这是我用来执行此操作的查询：

SELECT part_number,bin_location 
FROM list 
ORDER BY case when bin_location = 'xx' then part_number end

这是我得到的结果：

part_number       bin_location
Alaska wine           A1
German water          A2
London whisky         A3
German wine           C1
London water          A4
German wine           B2
London whisky         B3
German wine           A4
London whisky         C2
Water Green Wine      C3
Pure Water            D1
Orange whisky         D2
Ireland Moat          D3
French wine           XX
French water          XX
Ireland Moat          xx
Italy water           XX
Orange whisky         XX
Pure Water            XX
Water Green Wine      XX

正如您在xx子句满足后所看到的那样，它将part_number按顺序放置，但在此之前，bin位置不是。

我该如何解决这个问题？

提前致谢。

Answer 1

我想你想要：

SELECT part_number, bin_location
FROM list
ORDER BY (CASE WHEN bin_location = 'xx' THEN 1 ELSE 2 END),  -- put non-XX first
         (CASE WHEN bin_location <> 'xx' THEN bin_location END),
         part_number;

Answer 2

我认为不需要CASE声明。您可以按如下方式查询：

SELECT part_number, bin_location
  FROM list
 ORDER BY bin_location, part_number;

如果您打算bin_location不区分大小写（即xx和XX应该被视为相似），那么您可以这样做：

SELECT part_number, bin_location
  FROM list
 ORDER BY UPPER(bin_location), part_number;

希望这有帮助。

SQL顺序与案例没有正确排序

2 个答案: