Question

我正在尝试从时间记录表中为用户事务整理一些数据。这是一个简单的数据表，其中包含日期和销售完成或放弃的指标..

这是一些数据

UserId  TimeStamp MonthName Code        Cost
1   01/01/2018  January SALE_COMPLETE   115.00
1   02/01/2018  January SALE_COMPLETE   199.00
1   03/01/2018  January SALE_COMPLETE   177.00
1   12/01/2018  January SALE_ABANDONED  103.00
1   13/01/2018  January SALE_ABANDONED  126.00
1   14/01/2018  January SALE_ABANDONED  31.00
2   15/01/2018  January SALE_ABANDONED  141.00
2   16/01/2018  January SALE_ABANDONED  169.00
2   17/01/2018  January SALE_ABANDONED  216.00
2   18/01/2018  January SALE_ABANDONED  186.00
2   19/01/2018  January SALE_ABANDONED  239.00
2   20/01/2018  January SALE_ABANDONED  144.00
2   21/01/2018  January SALE_ABANDONED  160.00
2   22/01/2018  January SALE_ABANDONED  121.00
2   23/01/2018  January SALE_ABANDONED  168.00
2   24/01/2018  January SALE_ABANDONED  78.00
2   25/01/2018  January SALE_ABANDONED  160.00
2   26/01/2018  January SALE_ABANDONED  11.00
2   27/01/2018  January SALE_ABANDONED  128.00
2   28/01/2018  January SALE_ABANDONED  191.00
2   29/01/2018  January SALE_ABANDONED  232.00
2   30/01/2018  January SALE_ABANDONED  201.00
2   31/01/2018  January SALE_ABANDONED  109.00
2   01/02/2018  February    SALE_ABANDONED  160.00
2   02/02/2018  February    SALE_ABANDONED  103.00
2   03/02/2018  February    SALE_ABANDONED  146.00
2   04/02/2018  February    SALE_ABANDONED  22.00
2   05/02/2018  February    SALE_ABANDONED  74.00
2   06/02/2018  February    SALE_ABANDONED  102.00
2   07/02/2018  February    SALE_ABANDONED  66.00
2   08/02/2018  February    SALE_ABANDONED  118.00

我想要做的是在代码为SALE_ABANDONED并且代码大于或等于5个实例或每个用户的总费用>少于5个实例。最后将这几个月分组。

所以这就是我要回归的内容

MonthName   >=5 CostLoss    <5 CostLoss
January     2654               260
February     791                0

请注意，2月份UserId 2仍然符合＆gt; = 5类别，因为它继续从1月份的SALE_ABANDONED实例开始。

我希望这对某人真的有意义，我知道它非常棘手......

Answer 1

您需要嵌套的agregation，一个简单的计数加上条件聚合：

select MonthName, 
   -- split the counts in two groups, ">=" and "<"
   sum(case when cnt >= 5 then sumCost else 0 end) as ">=5 CostLoss",
   sum(case when cnt  < 5 then sumCost else 0 end) as "<5 CostLoss"
from
 ( -- number of abandoned sales per user/month
    select UserId, MonthName, 
        sum(cost) as sumCost,
        count(*) as cnt
    from myTable
    where Code = 'SALE_ABANDONED'
    group by UserId, MonthName
) as dt
group by MonthName

Answer 2

这将获得每月成本的总和，然后总结所有低于5和大于5的成本损失。

select MonthName, 
   sum(case when cnt >= 5 then sum_cost else 0 end) as ">=5 CostLoss",
   sum(case when cnt  < 5 then sum_cost else 0 end) as "<5 CostLoss"
from
 (  select UserId, 
           month(TStamp) as monthNum,
           MonthName,
           sum(Cost) as sum_cost,
           count(*) as cnt
    from yourTable
    where Code = 'SALE_ABANDONED'
    group by UserId, month(TStamp), MonthName
) as t
group by MonthName
order by monthNum  

Result:
   MonthName    >=5 CostLoss    <5 CostLoss
   January       2654            260
   February       791              0

当连续标准为真时，MySQL计数值

2 个答案: