Question

为什么JS sqrt（）函数不起作用？

CREATE TEMPORARY FUNCTION sqt(x int64)
RETURNS int64
LANGUAGE js AS """
  return sqrt(x);
""";

with table1 as(
select 25 as x union all 
select 100 as x union all 
select 625 as x 
)

select x,sqt(x)square_root from table1

错误：ReferenceError：sqt未定义为sqt（INT64）第2行，第2-3列

Answer 1

JavaScript函数是Math.sqrt。试试这个：

CREATE TEMPORARY FUNCTION sqt(x int64)
RETURNS int64
LANGUAGE js AS """
  return Math.sqrt(x);
""";

with table1 as(
select 25 as x union all 
select 100 as x union all 
select 625 as x 
)

select x,sqt(x)square_root from table1

请注意，INT64不是JavaScript UDF的官方支持类型（因为没有等效的JavaScript类型）。最好使用FLOAT64。

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1 个答案: