Question

我是Stack Overflow和Python的新手（但不是编程新手）

问题 - 为什么Trinket会显示运行时错误 -

TypeError: unsupported operand type(s) for Add: 'int' and 'list' on line 20 in main.py

在我看来，它认为l_score是一个列表，即使我已经在子例程中明确定义为int。如何将变量分配给数组的元素并保留已分配的变量类型，例如诠释？我已经标记了发生此错误的代码部分（以及我尝试过的替代方案）

# A program to total 3 input numbers

m_score = []
total = 0


def input_scores(): # def = define.
    for i in range(0,3):
      i_score = int(input("score"))
      m_score.append([i_score])
    #end for    
    return m_score # returns the value to the calling line
# end input_scores

def CalculateMean(m_score): # def =  define. 
    tot = 0
    l_score = int(0)
    for i in m_score:
      l_score = (m_score[1])
      tot = tot + l_score            # - QUESTION 
#      tot = tot + int(l_score)       This doesn't work either
#       tot = sum(m_score)          This doesn't work either 

      print('tot = ' + str(tot)) 
      return(tot)
    #end for
    return(total)
#end   CalculateQuartiles

input_scores()
for i in m_score:
  print(i)
#end for

total = CalculateMean(m_score)
print('Total = ' + str(total))

Answer 1

m_score目前是一个列表列表，因此m_score[1]仍然是一个列表，尽管只有一个项目。您可以在第1行中将其定义为空列表，然后在其中附加单项列表。

将m_score.append([i_score])更改为m_score.append(i_score)。

将变量分配给Trinket中数组/矩阵的单个元素的值

1 个答案: