Question

相对新手在这里..我正在尝试编写一个查询，其中有一个事务列表，我需要查看60天后是否发生了不同的事务类型

E.g. A
Trans 1 : 1/1/18
Trans 2 : 1/11/17, 1/12/17, 2/1/18, 1/2/18, 1/3/18, 17/3/18
Did a trans 2 occurs within 60 days post trans 1 : Y
-->  I don't want to return this example

...

E.g. B
Trans 1 : 1/1/18
Trans 2 : 1/11/17, 1/12/17, 31/12/17, 17/3/18, 21/3/18
Did a trans 2 occurs within 60 days post trans 1 : N
--> I want to return this example

...

SELECT * FROM
  (SELECT e.ID, sa.id                           ** LIST OF TRANSACTIONS #1* 
  FROM table1 e,
       table3 sa
  WHERE e.type_id   = 'ABC'
  AND sa.type_id    = 'PRE'
  ) S1,

  (SELECT sa.id, adj.date AS vdate              ** LIST OF TRANSACTIONS #2**
  FROM table4 sa,
    table5 adj
  WHERE sa.id = adj.id
  ) S2

WHERE S1.id = S2.id
and s2.vdate > S1.E_DT 

                ** ME TRYING TO COMPARE IF 1 date of TRANS 2 is after 60 days of TRANS 1** 

and s2.vdate < S1.E_DT + 60
and s2.vdate not between (S1.E_DT) and  (S1.E_DT + 60 )

Trans类型2将在trans类型1的过去和将来具有大范围的日期。

从我的谷歌搜索，我认为我需要一个案例选项或可能不存在？

你能指出我正确的方向吗？

由于萨拉

Answer 1

如果您想要在60天内没有交易＃2的交易＃1列表，我会使用NOT EXISTS：

select *
from
  (... your subquery ...) s1
where not exists
  (select 1 from  
      (...) s2
      where s1.id = s2.id
        and s2.vdate between s1.e_dt and s1.e_dt + 60);

如果你想看看所有的交易＃1并看到一个标志，显示他们是否在60天内跟随了＃2交易，我将NOT EXISTS移到SELECT子句中使用CASE。

select s1.*, 
    CASE WHEN not exists
          (select 1 from  
              (...) s2
              where s1.id = s2.id
                and s2.vdate between s1.e_dt and s1.e_dt + 60) 
         THEN 'Y' ELSE 'N' END as no_trans2_in_60_days
from
  (...) s1
;

您也可以将此作为外部联接，但就您的示例而言，我认为这不值得麻烦。

如果反式类型2是反式类型1的60天之后

1 个答案: