Question

作为参考，这是段落的样子。

{180319 arun S B} first set of chars. first chars.
{180316 yyay S B} second set of chars. second line.
{180314 ramaw S B} third line. third line. third line.
{180309 jfds S B} fouth line
{180221 shrbsd S B} fifth line.fith line part 2.
{180214 shrbs S B} sixth line.

在这里我需要提取前两行。像

{180319 arun S B} first set of chars. first chars.
{180316 yyay S B} second set of chars. second line.

我不知道如何在tcl中执行此操作。你能建议我这样做吗？虽然我是tcl的新手，但我已经上网了好几个小时，所以很难理解我。感谢

Answer 1

有几种方法可以做到这一点：

将段落拆分为行并加入前两行：

set lines [split $para \n]
set first2 [lrange $lines 0 1]
set wanted [join $first2 \n]
# or
set wanted [join [lrange [split $para \n] 0 1] \n]

找到第二个换行符的位置，并从段落开头到该位置取字符

set firstnewline [string first \n $para]
set secondnewline [string first \n $para $firstnewline+1]
set wanted [string range $para 0 $secondnewline-1]

您还可以使用

获取第二个换行符索引

set secondnewline [lindex [regexp -all -inline -indices \n $para] 1 0]

这里记录了Tcl命令：https://tcl.tk/man/tcl8.6/TclCmd/contents.htm

Answer 2

工作TCL代码将遵循：

 		set file [open c:/filename.txt ]
    	set file_device [read  $file]
    	set data [split $file_device "\n"]

        for {set count 0} {$count < 2} {incr count} {
        
        puts $data
        
        # for every iterartion one line will be printed.
    	# split /n is use for getting the end of each line.
        # open command open the file at given path. 
        # read command is use to read the open file.
    	}
    	close $file
    	break

这肯定会有用。

从段落中只获得tcl / tk

2 个答案: