**错误：**“未捕获的TypeError：无法读取属性'替换'未定义”？

Question

错误：“未捕获的TypeError：无法读取未定义的属性'replace'”？

jQuery(document).ready(function(){
    	var rep = jQuery(".abc")
              .clone()
              .wrap("<div></div>")
              .parent().html()
              .replace(/select/g,"ul")
              .replace(/option/g,"li");

    	jQuery(".abc").replaceWith(rep);
    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 1

我认为这符合预期：

＆＃13;

＆＃13;

        private Button firstWindowButton;
    public SecondWindow(Button firstWindowButton) {
        this.firstWindowButton = firstWindowButton;
        InitializeComponent();
    }
    private void Button_Click(object sender, RoutedEventArgs e)
    {
        firstWindowButton.Click += firstWindowButton_Click;
    }
    void firstWindowButton_Click(object sender, RoutedEventArgs e)
    {
        lblShowUser.Content = "First window button clicked on: " + DateTime.Now.ToString();
    }

<Label Name="lblShowUser" Content="" HorizontalAlignment="Left" Margin="275,175,0,0" VerticalAlignment="Top" Height="92" Width="205"/>

＆＃13;

jQuery(document).ready(function(){
	var rep = jQuery(".abc")
          .clone()
          .wrap("<div></div>")
          .parent().html()
          .replace(/select/g,"ul")
          .replace(/option/g,"li");

	jQuery(".abc").replaceWith(rep);
});

＆＃13;

＆＃13;

＆＃13;

也许您错过了网页上的<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="abc"> <select> <option>1</option> <option>2</option> </select> </div>元素。在这种情况下，.abc将返回.html()。