我正在尝试获取精确图像的最大边界矩形。我认为它有效,但我不知道如何可视化矩形。最后我想得到矩形的右边和右下坐标,但我认为当我能够将图像导入我的虚空时,我也可以从图像中获取这些值。我是新手,所以我正在学习,阅读和询问。如果我只是需要研究一些理论,请赐教!愿意学习。
当我运行此代码时,我的控制台输出是:
Emgu.CV.Util.VectorOfPoint
代码是这样的:
private void CannyFrame(object sender, EventArgs e)
{
if (_capture != null && _capture.Ptr != IntPtr.Zero)
{
_capture.Retrieve(imgOriginal, 0);
CvInvoke.CvtColor(imgOriginal, imgHSV, ColorConversion.Bgr2Hsv); //Convert the captured frame from BGR to HSV
CvInvoke.InRange(imgHSV, new ScalarArray(new MCvScalar(iLowH, iLowS, iLowV)), new ScalarArray(new MCvScalar(iHighH, iHighS, iHighV)), imgThres);
CvInvoke.Canny(imgThres, imgCanny, 100, 200, 3);
Form1.FindLargestContour(imgCanny, imgContour);
pictureBox3.Image = imgContour.Bitmap;
}
}
public static VectorOfPoint FindLargestContour(IInputOutputArray imgCanny, IInputOutputArray imgContour)
{
int largest_contour_index = 0;
double largest_area = 0;
VectorOfPoint largestContour;
using (Mat hierachy = new Mat())
using (VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint())
{
IOutputArray hierarchy;
CvInvoke.FindContours(imgCanny, contours, hierachy, RetrType.Tree, ChainApproxMethod.ChainApproxSimple);
for (int i = 0; i < contours.Size; i++)
{
MCvScalar color = new MCvScalar(0, 0, 255);
double a = CvInvoke.ContourArea(contours[i], false); // Find the area of contour
if (a > largest_area)
{
largest_area = a;
largest_contour_index = i; //Store the index of largest contour
}
CvInvoke.DrawContours(imgContour, contours, largest_contour_index, new MCvScalar(255, 0, 0));
}
CvInvoke.DrawContours(imgContour, contours, largest_contour_index, new MCvScalar(0, 0, 255), 3, LineType.EightConnected, hierachy);
largestContour = new VectorOfPoint(contours[largest_contour_index].ToArray());
}
Console.WriteLine(largestContour);
return largestContour;
}
答案 0 :(得分:0)
我通过制作
解决了我的问题public static VectorOfPoint FindLargestContour(IInputOutputArray imgCanny, IInputOutputArray imgContour)
进入
private static void FindLargestContour(IInputOutputArray imgCanny, IInputOutputArray imgContour)
在我删除的空白中
return largestContour;
不确定是否可行,但我的代码还是这样。