这是我的休息控制器代码
@RequestMapping(value = "/?username={username}&password={password}", method = RequestMethod.GET, produces = {MediaType.APPLICATION_JSON_VALUE})
@ResponseStatus(value= HttpStatus.OK)
public UserDetails getUserDetails(@PathVariable("username") String username , @PathVariable("password") String password )
{
System.out.println("This is controller"+username+","+password);
UserDetails userDetails = userService.loadUserByUsername(username);
System.out.println("Get Password "+userDetails.getPassword());
if(userDetails.getUsername().equals(username) && userDetails.getPassword().equals(password))
{
return userDetails;
}
return null;
}
当我在邮递员中传递url时,out pout将是
http://localhost:8080/hello/?username=abc@gmail.com&password=123456
out put必须返回json值,但它不会打印
答案 0 :(得分:0)
首先,遵循标准是有帮助的。
现在回答您的问题,在这种情况下您可以使用@RequestParam
。一个例子(因为我无法复制粘贴您的代码。请参阅!这会发生)。
@RequestMapping("urlstring")
public String printUserDept (@RequestParam("dept") String deptName) {
//your code
return "viewname";
}
,您的网址将为example.com/urlstring?dept=departmentname
答案 1 :(得分:0)
@RequestMapping(value = "/", method = RequestMethod.GET, produces = {MediaType.APPLICATION_JSON_VALUE})
@ResponseStatus(value= HttpStatus.OK)
public UserDetails getUserDetails(@RequestParam("username") String username , @RequestParam("password") String password )
{
System.out.println("This is controller"+username+","+password);
UserDetails userDetails = userService.loadUserByUsername(username);
System.out.println("Get Password "+userDetails.getPassword());
if(userDetails.getUsername().equals(username) && userDetails.getPassword().equals(password))
{
return userDetails;
}
return null;
}