Question

我正在尝试使用以下代码进行计算：

def traffic_intensity(count):
"""Number of cars passing by"""
int(count)
if count < 5000:
    level = "Very Low"
elif 5000 <= count < 10000:
    level = "Low"
elif 10000 <= count < 18000:
    level = "Moderate"
elif count >= 18000:
    level = "High"
return level


def number_of_busy_days(counts):
    """Busy days based on traffic flow"""
    daily_counts = 0
    for count in counts:
        if traffic_intensity(level) == "Moderate" or "High":
            daily_counts = daily_counts + 1
    return daily_counts

counts = [18000, 10000, 500, 9999, 12000]
print(number_of_busy_days(counts))

我想要实现的是使用traffic_intensity函数来计算忙碌天数 - 忙碌的一天被定义为具有超过traffic_intensity函数中给出的“中等”流量的量。我尝试了很多不同的方法，但此时我的想法已经不多了。

我遇到的问题是它没有从第一个函数中找到级别变量。我收到以下错误：

    if traffic_intensity(level) == "Moderate" or "High":
    NameError: name 'level' is not defined

有人能帮助我吗？谢谢！ ^ _ ^

Answer 1

您传入的函数traffic_intensity中不存在变量level。我认为你打算传入变量count。

同样，将or "High"作为条件将始终为true，因为非空字符串在python中可转换为true

def traffic_intensity(count):
    """Number of cars passing by"""
    int(count)
    if count < 5000:
        level = "Very Low"
    elif 5000 <= count < 10000:
        level = "Low"
    elif 10000 <= count < 18000:
        level = "Moderate"
    elif count >= 18000:
        level = "High"
    return level


def number_of_busy_days(counts):
    """Busy days based on traffic flow"""
    daily_counts = 0
    for count in counts:
        state = traffic_intensity(count)
        if state == "Moderate" or state == "High":
            daily_counts = daily_counts + 1
    return daily_counts

counts = [18000, 10000, 500, 9999, 12000]
print(number_of_busy_days(counts))

在函数之间转发变量

1 个答案: