boost :: serialization库中是否可以使用引用反序列化(多态)对象而没有默认构造函数?
class Example
{
int& value;
public:
Example(int _value): value(_value) {}
virtual ~Example() {}
friend class boost::serialization::access;
template<typename Archive>
void serialize(Archive & ar, const unsigned int file_version)
{
ar & value;
}
};
class Usage
{
Example* example;
public:
Usage(): example(new Example(123)) {}
~Usage() { delete example; }
friend class boost::serialization::access;
template<typename Archive>
void serialize(Archive & ar, const unsigned int file_version)
{
ar & example;
}
};
...
// serialize and deserialize object with reference and no default constructor
{
Usage source;
std::ostringstream oss;
boost::archive::text_oarchive oa(oss);
oa & source;
Usage target;
std::istringstream iss(oss.str());
boost::archive::text_iarchive ia(iss);
ia & target; // does not compile
}
答案 0 :(得分:5)
对于非默认的可构造对象,我建议查看该项目
非默认构造函数
here。
您的课程可以序列化
编写自己的功能模板load_construct_data
和save_construct_data
。