我有一个表MY_DATES (START_DATE DATE, END_DATE DATE)
,其数据如下:
START_DATE END_DATE
---------------------------
18-DEC-17 07-JAN-18
27-JAN-18 06-FEB-18
08-MAR-18 18-MAR-18
我需要使用如下所示的SQL在单个列中生成表格中所有日期范围的日期:
DATES
----------
18-DEC-17
19-DEC-17
20-DEC-17
.
.
.
06-JAN-18
07-JAN-18
27-JAN-18
28-JAN-18
29-JAN-18
.
.
.
05-FEB-18
06-FEB-18
08-MAR-18
09-MAR-18
10-MAR-18
.
.
.
18-MAR-18
我正在使用oracle 11G。感谢这方面的任何帮助。
答案 0 :(得分:2)
试试这个。
WITH t (sdt, ldt) AS (SELECT MIN (START_DATE), MAX (END_DATE) FROM MY_DATES)
SELECT *
FROM ( SELECT sdt + LEVEL - 1 AS dates
FROM t
CONNECT BY LEVEL <= ldt - sdt + 1) c
WHERE EXISTS
(SELECT 1
FROM MY_DATES d
WHERE c.dates BETWEEN START_DATE AND END_DATE);
答案 1 :(得分:1)
Tro要做到这一点:
with calendar as (
select :startdate + rownum - 1 as day
from dual
connect by rownum < :enddate - :startdate
)
select rownum as "S.No",
to_date(day,'dd_mm_yyyy') as "Cal_Dt",
to_char(day,'day') as "DayName"
from calendar
你必须替换:startdate和:enddate,其中包含特定情况的有意义值。
答案 2 :(得分:0)
在这种情况下,将生成AVG费用并将其分布在日期范围内的月末所有日期。
CREATE table #ProductSales (ProjectID Int, ProjectName varchar(100), TotalBillableFees Money, StartDate Date, EndDate Date, DataDate Date)
Insert into #ProductSales
Values
(373104,'Product Sales - Flex Creation Test',40000.00,'2019-04-01','2020-06-01','2019-08-01'),
(375111,'Product Sales - SMART',40000.00,'2019-04-01','2019-09-01','2019-08-01')
;WITH Dates AS (
SELECT ProjectiD
,Convert(decimal(10,2),TotalBillableFees/IIF(DATEDIFF(MONTH,StartDate,EndDate)=0,1,DATEDIFF(MONTH,StartDate,EndDate))) AS BillableFeesPerMonths,EndDate
,[Date] = CONVERT(DATETIME,EOMONTH(StartDate))
FROM #ProductSales
UNION ALL SELECT ProjectiD,BillableFeesPerMonths,EndDate,
[Date] = DATEADD(MONTH, 1, [Date])
FROM
Dates
WHERE
Date < EOMONTH(EndDate)
) SELECT ProjectID,BillableFeesPerMonths,
CAST([Date] as Date) Date
FROM
Dates
OPTION (MAXRECURSION 45)