Question

我的MySQL技能非常基础，所以我想得到的是团队1的名称，表格的团队2来自表团队，在一个SELECT语句中（如果可能的话）。我有一个声明，但我只得到团队2中团队1的名称我得到了与团队1相同的名称

小组表

---------------------------------------
- team_id  - team_title  - team_image -
---------------------------------------
-        1 - Brazil      - br.png     -
-        2 - Russia      - ru.png     -
-        3 - Spain       - es.png     -
---------------------------------------

匹配表

------------------------------------------
- match_id  - match_team1  - match_team2 -
------------------------------------------
-         1 -            2 -           3 -
-         2 -            1 -           2 -
-         3 -            3 -           1 -
------------------------------------------

功能

function get_all_matches($connect)
{

    $sentence = $connect->prepare("
    SELECT matches.*
         , teams.team_title 
      FROM matches
         , teams 
     WHERE matches.match_team1 = teams.team_id 
     ORDER 
        BY matches.match_id DESC
        "); 
    $sentence->execute();
    return $sentence->fetchAll();
}

Answer 1

您需要两个联接，每个联接用于您要检索的每个团队名称。

另外，请注意隐式连接（在from子句中有多个表）已被认为已弃用很长一段时间了，您应该使用现代显式join子句：< / p>

SELECT   m.*,
         t1.team_title AS team_1_title,
         t2.team_title AS team_2_title
FROM     matches m
JOIN     teams t1 ON m.match_team1 = t1.team_id 
JOIN     teams t2 ON m.match_team2 = t2.team_id 
ORDER BY m.match_id DESC

Answer 2

你有没有试过像

这样的东西

 Select A.match_team1, t1.team_title,  
       A.match_team2, t2.team_title   
 FROM matches A                       
      left outer join teams t2        
        on A.match_team2 = t2.team_id,
      teams T1                        
 WHERE A.match_team1 = t1.team_id

我不熟悉MySql，但是我猜应该支持加入。

从相同的表字段中选择不同的字段 - Mysql

2 个答案: