我正在尝试打开一个伴随DICOM的.jpeg file文件。这对文件是从成像设备导出图像采集的结果，我猜这是一个专有的DICOM。除了查看实际图像数据外，我仍然可以阅读文件的信息和标签。
我正在使用PyDicom并执行以下操作：
import pydicom
myfile = pydicom.read_file("thedicomfile.dcm")
myfile.pixel_array # results in error
AttributeError: 'Dataset' object has no attribute 'TransferSyntaxUID'
# so I do
myfile.file_meta.TransferSyntaxUID = pydicom.uid.ImplicitVRLittleEndian
# then
myfile.pixel_array
lAttributeError：像素数据量19404与预期数据76800不匹配
我不知道该怎么做或如何利用我的DICOM附带的.jpg文件中的信息。
（数据属于我自己，也随机改变了出生时间，因此保密性没有问题）
Hex dump of file 1:
file name: 1_DThumbN.jpg
mime type:
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0000-0be0: 20 c7 19 1f-fe aa 77 f0-7d 3a f3 d4-71 40 07 98 ......w. }:..q@..
0000-0bf0: 4f df 25 f9-cf 27 8a 6f-eb 49 bb 82-56 03 d4 8e O.%..'.o .I..V...
0000-0c00: 3d 29 28 18-b8 ff 00 3e-b4 94 80 5c-7b 8a 4a 60 =)(....> ...\{.J`
0000-0c10: 14 76 a4 01-45 30 17 8c-7b d2 b1 04-e7 9e 7a e4 .v..E0.. {.....z.
0000-0c20: e6 81 0d ef-4b 9e 28 18-0e 0f 34 94-00 b8 e3 34 ....K.(. ..4....4
0000-0c30: 94 00 0e 28-a0 02 8a 40-14 50 02 8a-4a 00 3f 1a ...(...@ .P..J.?.
0000-0c40: 5e dd 29 80-94 b4 80 07-1c d2 53 00-fa d1 40 0a ^.)..... ..S...@.
0000-0c50: 7d a9 29 00-51 40 05 14-00 52 8a 60-25 29 c0 c7 }.).Q@.. .R.`%)..
0000-0c60: 1f 5a 40 25-2e 78 c5 00-19 ce 79 a4-a0 05 cf 5e .Z@%.x.. ..y....^
0000-0c70: 07 3f a5 25-00 1d 7a 51-40 05 14 00-a4 92 72 4e .?.%..zQ @.....rN
0000-0c80: 4d 25 00 14-1a 00 28 ed-40 05 29 39-3e b4 c0 01 M%....(. @.)9>...
0000-0c90: 20 10 0f 5e-0d 04 e4 01-e8 3d 29 00-94 50 01 fc ...^.... .=)..P..
0000-0ca0: a8 a0 02 8a-00 29 73 f4-e2 80 12 8a-00 28 a0 02 .....)s. .....(..
0000-0cb0: 8a 00 28 a0-02 8a 00 28-a0 03 ad 14-00 51 40 05 ..(....( .....Q@.
0000-0cc0: 14 00 51 40-05 14 00 51-40 05 14 00-02 41 c8 e0 ..Q@...Q @....A..
0000-0cd0: d1 40 05 14-00 52 8f ad-30 12 97 9e-87 23 06 80 .@...R.. 0....#..
0000-0cd6: 0c 7a 73 49-48 0f .zsIH.
Hex dump of file 2:
file name: 1_Video.dcm
mime type:
0000-0010: cc 4b 00 00-00 00 00 00-00 00 00 00-00 00 00 00 .K...... ........
0000-0020: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0030: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0040: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0050: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0060: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0070: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0080: 00 00 00 00-00 00 00 00-00 00 00 00-00 00 00 00 ........ ........
0000-0090: 44 49 43 4d-08 00 18 00-55 49 34 00-31 35 46 44 DICM.... UI4.15FD
0000-00a0: 41 36 34 2d-37 37 34 36-2d 34 36 43-46 2d 39 38 A64-7746 -46CF-98
0000-00b0: 44 42 2d 30-30 33 43 45-30 35 31 42-39 46 33 2e DB-003CE 051B9F3.
0000-00c0: 35 31 33 31-2e 31 36 37-35 34 2e 36-31 39 35 36 5131.167 54.61956
0000-00d0: 08 00 20 00-44 41 08 00-32 30 30 37-30 39 31 38 ....DA.. 20070918
0000-00e0: 08 00 21 00-44 41 08 00-32 30 30 37-30 39 31 38 ..!.DA.. 20070918
0000-00f0: 08 00 31 00-54 4d 06 00-31 36 33 36-34 30 08 00 ..1.TM.. 163640..
0000-0100: 32 00 54 4d-06 00 31 36-33 36 34 31-08 00 60 00 2.TM..16 3641..`.
0000-0110: 43 53 04 00-4f 43 54 20-08 00 70 00-4c 4f 12 00 CS..OCT. ..p.LO..
0000-0120: 43 61 72 6c-20 5a 65 69-73 73 20 4d-65 64 69 74 Carl.Zei ss.Medit
0000-0130: 65 63 08 00-10 10 53 48-04 00 4f 43-54 33 08 00 ec....SH ..OCT3..
0000-0140: 90 10 4c 4f-04 00 33 30-30 30 10 00-10 00 50 4e ..LO..30 00....PN
0000-0150: 06 00 63 33-5e 32 30 34-10 00 20 00-4c 4f 08 00 ..c3^204 ....LO..
0000-0160: 31 33 36 35-33 37 37 20-10 00 30 00-44 41 08 00 1365377. ..0.DA..
0000-0170: 31 39 34 35-30 31 31 32-10 00 40 00-43 53 02 00 19450112 ..@.CS..
0000-0180: 4d 20 10 00-54 21 53 48-02 00 5c 20-10 00 60 21 M...T!SH ..\...`!
0000-0190: 53 48 06 00-57 68 69 74-65 20 10 00-00 40 4c 54 SH..Whit e....@LT
0000-01a0: 00 00 18 00-00 10 4c 4f-0a 00 33 30-30 30 2d 36 ......LO ..3000-6
0000-01b0: 37 30 37 20-18 00 20 10-4c 4f 0c 00-34 2e 30 2e 707..... LO..4.0.
0000-01c0: 37 20 28 30-31 33 32 29-20 00 0d 00-55 49 28 00 7.(0132) ....UI(.
0000-01d0: 31 35 46 44-41 36 34 2d-37 37 34 36-2d 34 36 43 15FDA64- 7746-46C
0000-01e0: 46 2d 39 38-44 42 2d 30-30 33 43 45-30 35 31 42 F-98DB-0 03CE051B
0000-01f0: 39 46 33 2e-35 31 33 31-20 00 0e 00-55 49 2e 00 9F3.5131 ....UI..
答案 0 :(得分：6)
您偶然发现了一个包含多个不符合DICOM标准的文件。最关键的是缺少文件元头，其中包括文件的传输语法。它还包括原始标识符值（例如15FDA64-7746-46CF-98DB-003CE051B9F3.5131.16754.61956），它们不是有效的UID（由于存在连字符），以及一些其他不一致性。这使得使用开放的，符合标准的工具和库进行操作变得更加困难。一旦传输语法未知，就需要以某种方式做出外部假设。
但在这种特殊情况下，一切都没有丢失。 dcmdump工具通过检测ExplicitVRLittleEndian作为转移语法，设法恢复了一些属性（为简洁起见，删除了一些部分）：
# Dicom-File-Format
# Dicom-Meta-Information-Header
# Used TransferSyntax: Unknown Transfer Syntax
# Dicom-Data-Set
# Used TransferSyntax: Little Endian Explicit
(0008,0018) UI [15FDA64-7746-46CF-98DB-003CE051B9F3.5131.16754.61956] # 52, 1 SOPInstanceUID
[...]
(0008,0060) CS [OCT] # 4, 1 Modality
[...]
(0028,0002) US 1 # 2, 1 SamplesPerPixel
(0028,0004) CS [MONOCHROME2] # 12, 1 PhotometricInterpretation
(0028,0010) US 240 # 2, 1 Rows
(0028,0011) US 320 # 2, 1 Columns
(0028,0034) IS [1\1] # 4, 2 PixelAspectRatio
(0028,0100) US 8 # 2, 1 BitsAllocated
(0028,0101) US 8 # 2, 1 BitsStored
(0028,0102) US 7 # 2, 1 HighBit
(0028,0103) US 0 # 2, 1 PixelRepresentation
[...]
(7fe0,0010) OW 0000\0c00\506a\2020\0a0d\0a87\0000\1800\7466\7079\706a\2078\0000... # 19404, 1 PixelData
检索像素数据的必要细节似乎乍一看。但是，PixelData的长度为19404字节，而原始的320x240x1位图则需要76800字节。这是pydicom最终失败的地方，因为它试图将像素数据作为未压缩的像素数组读取。此时我们可以假设图像数据处于某种其他编码中。将DICOM元素值写入单独的文件：
with open('PixelData.bin', mode='wb') as f:
f.write(myfile.PixelData)
我们可以使用file进行魔术测试：
$ file PixelData.bin
PixelData.bin: JPEG 2000 Part 2 (JPX)
PixelData字段包含JPEG 2000图像文件。 PIL图像模块可以处理格式，因此我们可以在没有pydicom帮助的情况下手动将数据转换为数组。根据{{3}}：
from PIL import Image
import io
image = Image.open(io.BytesIO(myfile.PixelData))
pixels = np.array(image.getdata()).reshape((myfile.Columns, myfile.Rows))
总结：