Question

package loginphp;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;

public class Loginphp {

    public static void main(String[] args) throws MalformedURLException, IOException {
        String url = "http://localhost/login/login.php";
        String Parameters = "username=admin&password=admin";
        byte[] postdata = Parameters.getBytes("UTF-8");
        String useragent = "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:59.0) Gecko/20100101 Firefox/59.0";
        URL urlLink = new URL(url);

        HttpURLConnection urlConn = (HttpURLConnection) urlLink.openConnection();
        urlConn.setRequestMethod("POST");
        urlConn.setRequestProperty("User-Agent", useragent);
       urlConn.setRequestProperty("Content-Length", String.valueOf(postdata.length));
        urlConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
        urlConn.setInstanceFollowRedirects(true);
        urlConn.setDoOutput(true);
        urlConn.getOutputStream().write(postdata);

        System.out.println("Connecting to " + url);
        System.out.println("Response " + urlConn.getResponseMessage());
        System.out.println("Code " + urlConn.getResponseCode());

        InputStream is = urlConn.getInputStream();
        InputStreamReader isr = new InputStreamReader(is);
        BufferedReader bis = new BufferedReader(isr);

        String output;

        while ((output = bis.readLine()) != null) {

            System.out.println(" " + output);
        }

    }

}

我发送了一个帖子请求到以下代码，但是它在登录后没有重定向到欢迎页面，我不确定它是否登录。结果我得到的是与登录页面相同的代码。可能是什么问题呢？我的主要目标是记录并重定向到welcome.php。该脚本使用浏览器完美运行。能够记录，重定向到欢迎页面并注销。

<?php
   include("config.php");
   session_start();
   $error = "";
   if($_SERVER["REQUEST_METHOD"] == "POST") {
      // username and password sent from form 

      $myusername = mysqli_real_escape_string($db,$_POST['username']);
      $mypassword = mysqli_real_escape_string($db,$_POST['password']); 

      $sql = "SELECT id FROM admin WHERE username = '$myusername' and passcode = '$mypassword'";
      $result = mysqli_query($db,$sql);
      $row = mysqli_fetch_array($result,MYSQLI_ASSOC);
      $active = $row['active'];

      $count = mysqli_num_rows($result);

      // If result matched $myusername and $mypassword, table row must be 1 row

      if($count == 1) {
        // session_register("myusername");
         $_SESSION['login_user'] = $myusername;

         header("location: welcome.php");
      }else {
         $error = "Your Login Name or Password is invalid";
      }
   }
?>
<html>

   <head>
      <title>Login Page</title>

      <style type = "text/css">
         body {
            font-family:Arial, Helvetica, sans-serif;
            font-size:14px;
         }

         label {
            font-weight:bold;
            width:100px;
            font-size:14px;
         }

         .box {
            border:#666666 solid 1px;
         }
      </style>

   </head>

   <body bgcolor = "#FFFFFF">

      <div align = "center">
         <div style = "width:300px; border: solid 1px #333333; " align = "left">
            <div style = "background-color:#333333; color:#FFFFFF; padding:3px;"><b>Login</b></div>

            <div style = "margin:30px">

               <form action = "" method = "post">
                  <label>UserName  :</label><input type = "text" name = "username" class = "box"/><br /><br />
                  <label>Password  :</label><input type = "password" name = "password" class = "box" /><br/><br />
                  <input type = "submit" value = " Submit "/><br />
               </form>

               <div style = "font-size:11px; color:#cc0000; margin-top:10px"><?php echo $error; ?></div>

            </div>

         </div>

      </div>

   </body>
</html>

Answer 1

简短的回答是你应该使用303 redirect：

header("HTTP/1.1 303 See Other");
header("location: welcome.php");

Java Networking Post Resquest

1 个答案: