13期间日历4-4-5日历T-SQL MSSQL

Question

我正在尝试在mssql中创建一个13期日历，但我有点卡住了。我不确定我的方法是否是实现这一目标的最佳方法。我有我的基本脚本，可以在下面看到：

Set DateFirst  1

Declare @Date1 date = '20180101' --startdate should always be start of 
financial year
Declare @Date2 date = '20181231' --enddate should always be start of 
financial year

SELECT * INTO #CalendarTable
FROM dbo.CalendarTable(@Date1,@Date2,0,0,0)c
DECLARE @StartDate datetime,@EndDate datetime

SELECT @StartDate=MIN(CASE WHEN [Day]='Monday' THEN [Date] ELSE NULL END),
@EndDate=MAX([Date])
FROM #CalendarTable

;With Period_CTE(PeriodNo,Start,[End])
AS
(SELECT 1,@StartDate,DATEADD(wk,4,@StartDate) -1
UNION ALL
SELECT PeriodNo+1,DATEADD(wk,4,Start),DATEADD(wk,4,[End])
FROM Period_CTE
WHERE DATEADD(wk,4,[End])< =@EndDate
OR PeriodNo+1 <=13
)
select * from Period_CTE

这给了我这个：

PeriodNo Start End 1 2018-01-01 00:00:00.000 2018-01-28 00:00:00.000 2 2018-01-29 00:00:00.000 2018-02-25 00:00:00.000 3 2018-02-26 00:00:00.000 2018-03-25 00:00:00.000 4 2018-03-26 00:00:00.000 2018-04-22 00:00:00.000 5 2018-04-23 00:00:00.000 2018-05-20 00:00:00.000 6 2018-05-21 00:00:00.000 2018-06-17 00:00:00.000 7 2018-06-18 00:00:00.000 2018-07-15 00:00:00.000 8 2018-07-16 00:00:00.000 2018-08-12 00:00:00.000 9 2018-08-13 00:00:00.000 2018-09-09 00:00:00.000 10 2018-09-10 00:00:00.000 2018-10-07 00:00:00.000 11 2018-10-08 00:00:00.000 2018-11-04 00:00:00.000 12 2018-11-05 00:00:00.000 2018-12-02 00:00:00.000 13 2018-12-03 00:00:00.000 2018-12-30 00:00:00.000

我想要的结果是 Angular documentation

即使我不得不采取不同的方法，我也不介意，只要结果与上述相同。

dbo.CalendarTable（）是一个返回以下结果的函数。如果需要，我可以分享代码。

Answer 1

我要创建一个通用号码表like suggested here并添加一列Periode13。

获取平铺的技巧是整数除法：

DECLARE @PeriodeSize INT=28; --13 "moon-months" a 28 days

SELECT TOP 100 (ROW_NUMBER() OVER(ORDER BY (SELECT NULL))-1)/@PeriodeSize
FROM master..spt_values --just a table with many rows to show the principles

您可以使用简单的更新语句将其添加到现有数字表中。

更新一个完整的工作示例（使用上面链接的逻辑）

DECLARE @RunningNumbers TABLE  (Number INT NOT NULL
                               ,CalendarDate DATE NOT NULL
                               ,CalendarYear INT NOT NULL
                               ,CalendarMonth INT NOT NULL
                               ,CalendarDay INT NOT NULL
                               ,CalendarWeek INT NOT NULL
                               ,CalendarYearDay INT NOT NULL
                               ,CalendarWeekDay INT NOT NULL);

DECLARE @CountEntries INT = 100000;
DECLARE @StartNumber INT = 0;


WITH E1(N) AS(SELECT 1 FROM(VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1))t(N)), --10 ^ 1
    E2(N) AS(SELECT 1 FROM E1 a CROSS JOIN E1 b), -- 10 ^ 2 = 100 rows
    E4(N) AS(SELECT 1 FROM E2 a CROSS JOIN E2 b), -- 10 ^ 4 = 10,000 rows
    E8(N) AS(SELECT 1 FROM E4 a CROSS JOIN E4 b), -- 10 ^ 8 = 10,000,000 rows
    CteTally AS
    (
        SELECT TOP(ISNULL(@CountEntries,1000000)) ROW_NUMBER() OVER(ORDER BY(SELECT NULL)) -1 + ISNULL(@StartNumber,0) As Nmbr
        FROM E8
    )
INSERT INTO @RunningNumbers
SELECT CteTally.Nmbr,CalendarDate.d,CalendarExt.*
FROM CteTally
CROSS APPLY
(
    SELECT DATEADD(DAY,CteTally.Nmbr,{ts'2018-01-01 00:00:00'})
) AS CalendarDate(d)
CROSS APPLY
(
    SELECT YEAR(CalendarDate.d) AS CalendarYear
          ,MONTH(CalendarDate.d) AS CalendarMonth
          ,DAY(CalendarDate.d) AS CalendarDay
          ,DATEPART(WEEK,CalendarDate.d) AS CalendarWeek
          ,DATEPART(DAYOFYEAR,CalendarDate.d) AS CalendarYearDay
          ,DATEPART(WEEKDAY,CalendarDate.d) AS CalendarWeekDay
) AS CalendarExt;

- 上面的模型表现已填写，可以查询

 WITH AddPeriode AS
(
    SELECT     Number/28 +1 AS PeriodNumber
              ,CalendarDate
              ,CalendarWeek
              ,r.CalendarDay 
              ,r.CalendarMonth 
              ,r.CalendarWeekDay 
              ,r.CalendarYear 
              ,r.CalendarYearDay 
    FROM @RunningNumbers AS r
)
SELECT TOP 100 p.*
          ,(SELECT MIN(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber) AS [Start]
          ,(SELECT MAX(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber) AS [End]
          ,(SELECT MIN(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber AND x.CalendarWeek=p.CalendarWeek) AS [wkStart]
          ,(SELECT MAX(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber AND x.CalendarWeek=p.CalendarWeek) AS [wkEnd]
          ,(ROW_NUMBER() OVER(PARTITION BY PeriodNumber ORDER BY CalendarDate)-1)/7+1 AS WeekOfPeriode
FROM AddPeriode AS p
ORDER BY CalendarDate

尝试一下......

提示：请勿使用VIEW或iTVF。

这是不变的数据，并且更好地放置在具有适当索引的物理存储表中。

Answer 2

这里并没有充分肯定外部链接，但我写了一篇文章，提到5-4-4＆＃39; Crop Year＆＃39;财政年度包含所有代码。随意使用这些文章中的所有代码。

SQL Server Calendar Table

SQL Server Calendar Table: Fiscal Years