Question

我的鳕鱼是那个，这个错误出现在课程的最后一行，我该怎么做才能解决它？

public class SSID {
            class func fetchSSIDInfo() -> String {
                var currentSSID = ""
                if let interfaces = CNCopySupportedInterfaces() {
                    for i in 0..<CFArrayGetCount(interfaces) {
                        let interfaceName: UnsafeRawPointer = CFArrayGetValueAtIndex(interfaces, i)
                        let rec = unsafeBitCast(interfaceName, to: AnyObject.self)
                        let unsafeInterfaceData = CNCopyCurrentNetworkInfo("\(rec)" as CFString)
                        if unsafeInterfaceData != nil {
                            let interfaceData = unsafeInterfaceData! as Dictionary!
                            currentSSID = interfaceData?["SSID"] as String
                        }
                    }
                }
                return currentSSID
            }
        }

Answer 1

使用下标的唯一行是：

let interfaceData = unsafeInterfaceData! as Dictionary!
currentSSID = interfaceData?["SSID"] as String

使用如下字符串访问：interfaceData?["SSID"]要求您以不同方式定义字典，当前字典声明为[NSObject: AnyObject]但要使用字符串下标，则需要[String: AnyObject]

尝试将此行更改为：

let interfaceData = unsafeInterfaceData! as [String: AnyObject]

注意：最好使用if而不是强制使用!

进行展开

Answer 2

你可以尝试

if  let interfaceData = unsafeInterfaceData! as? [String:Any]
{
    currentSSID = interfaceData["SSID"] as? String
}

不能下标'[NSObject：AnyObject]类型的值吗？索引类型为'String'Swift Error

2 个答案: