我遇到了查询问题。
我正在使用phpMyAdmin和MySQL。
我试图报告所有活跃客户（in ___Kardex where KDX_Status='active'）和：
in ___Bookings where BOO_Status!='cancel'）。in ___Bookings where BOO_Status!='cancel'）。为清楚起见，这里是一个样本数据集
CREATE TABLE `___Bookings` (
`BOO_Id` int(10) NOT NULL AUTO_INCREMENT,
`BOO_HotelId` varchar(20) NOT NULL,
`BOO_ClientId` int(10) NOT NULL,
`BOO_CompanyId` int(10) NOT NULL,
`BOO_BillingId` int(10) NOT NULL,
`BOO_DateCI` date NOT NULL,
`BOO_DateCO` date NOT NULL,
`BOO_Status` enum('confirmed','notconfirmed','option','cancel','checkin','checkout') NOT NULL,
UNIQUE KEY `BOO_Id` (`BOO_Id`),
KEY `id` (`BOO_Id`)
) ENGINE=MyISAM AUTO_INCREMENT=73 DEFAULT CHARSET=utf8;
INSERT INTO `___Bookings` VALUES
(70,'cus_CNHLMiMOzP5cuM',18,0,30,'2018-03-07','2018-03-12','confirmed'),
(71,'cus_CNHLMiMOzP5cuM',61,62,0,'2018-03-01','2018-03-02','cancel'),
(72,'cus_CNHLMiMOzP5cuM',19,0,0,'2018-03-04','2018-03-06','confirmed'),
(73,'cus_CNHLMiMOzP5cuM',61,0,0,'2018-03-01','2018-03-09','notconfirmed'),
(74,'cus_CNHLMiMOzP5cuM',61,0,0,'2018-03-10','2018-03-11','notconfirmed'),
(75,'cus_CNHLMiMOzP5cuM',19,62,63,'2018-03-10','2018-03-21','option');
CREATE TABLE `___Hotels` (
`HOT_HotelId` varchar(20) NOT NULL,
`HOT_AutoLabel_VIP_Bookings` tinyint(4) NOT NULL,
`HOT_AutoLabel_VIP_Nights` tinyint(4) NOT NULL,
`HOT_AutoLabel_Regular_Bookings` tinyint(4) NOT NULL,
`HOT_AutoLabel_Regular_Nights` tinyint(4) NOT NULL,
`HOT_Status` enum('active','inactive','pending') NOT NULL,
PRIMARY KEY (`HOT_HotelId`),
UNIQUE KEY `HOT_HotelId` (`HOT_HotelId`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
INSERT INTO `___Hotels` VALUES
('cus_CNHLMiMOzP5cuM', 10, 15, 20, 25, 'active');
CREATE TABLE `___Kardex` (
`KDX_Id` int(10) NOT NULL AUTO_INCREMENT,
`KDX_HotelId` varchar(20) NOT NULL,
`KDX_Type` enum('client','company','billing') NOT NULL,
`KDX_Status` enum('active','inactive') NOT NULL,
UNIQUE KEY `KDX_Id` (`KDX_Id`),
KEY `id` (`KDX_Id`)
) ENGINE=MyISAM AUTO_INCREMENT=63 DEFAULT CHARSET=utf8;
INSERT INTO `___Kardex` VALUES
(18,'cus_CNHLMiMOzP5cuM','client','active'),
(19,'cus_CNHLMiMOzP5cuM','client','active'),
(30,'cus_CNHLMiMOzP5cuM','billing','active'),
(61,'cus_CNHLMiMOzP5cuM','client','active'),
(62,'cus_CNHLMiMOzP5cuM','company','inactive'),
(63,'cus_CNHLMiMOzP5cuM','company','active'),
(91,'cus_CNHLMiMOzP5cuM','company','active'),
(92,'cus_CNHLMiMOzP5cuM','company','active');
......我最近的努力......
SELECT KDX_Id, KDX_Type,
(
SELECT COUNT(BOO_Id)
FROM ___Bookings
WHERE BOO_Status!='cancel'
AND (
KDX_Id = ___Bookings.BOO_ClientId
OR KDX_Id = ___Bookings.BOO_CompanyId
OR KDX_Id = ___Bookings.BOO_BillingId
)
) AS nb_bookings,
(
SELECT SUM(DATEDIFF(___Bookings.BOO_DateCO, ___Bookings.BOO_DateCI))
FROM ___Bookings
WHERE BOO_Status!='cancel'
AND (
KDX_Id = ___Bookings.BOO_ClientId
OR KDX_Id = ___Bookings.BOO_CompanyId
OR KDX_Id = ___Bookings.BOO_BillingId
)
) AS nb_nights,
HOT_HotelId,
HOT_AutoLabel_VIP_Bookings,
HOT_AutoLabel_VIP_Nights,
HOT_AutoLabel_Regular_Bookings,
HOT_AutoLabel_Regular_Nights
FROM ___Kardex
JOIN ___Hotels
ON ___Kardex.KDX_HotelId = ___Hotels.HOT_HotelId
JOIN ___Bookings
ON ___Kardex.KDX_HotelId = ___Bookings.BOO_HotelId
WHERE KDX_Status='active'
AND HOT_Status='active'
GROUP BY KDX_Id
和SQLFiddle相同：
http://sqlfiddle.com/#!9/67775f/1
所需的输出应该像我上面的SQLFiddle一样，除了第91行和第92行，因为我没有为这两个条目显示任何预订或夜晚。
实际上，查询会返回带有NULL或0条目的行。
预期结果
| KDX_Id | KDX_Type | nb_bookings | nb_nights | HOT_HotelId | HOT_AutoLabel_VIP_Bookings | HOT_AutoLabel_VIP_Nights | HOT_AutoLabel_Regular_Bookings | HOT_AutoLabel_Regular_Nights |
|--------|----------|-------------|-----------|--------------------|----------------------------|--------------------------|--------------------------------|------------------------------|
| 18 | client | 1 | 5 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 19 | client | 2 | 13 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 30 | billing | 1 | 5 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 61 | client | 2 | 9 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 63 | company | 1 | 11 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
任何帮助将不胜感激。
感谢。
答案 0 :(得分：3)
我已经重写了查询，因此您不需要GROUP BY来过滤重复项。
<强>查询
SELECT
kardex_bookings.KDX_id
, kardex_bookings.KDX_type
, kardex_bookings.nb_bookings
, kardex_bookings.nb_nights
, hotels.HOT_HotelId
, hotels.HOT_AutoLabel_VIP_Bookings
, hotels.HOT_AutoLabel_VIP_Nights
, hotels.HOT_AutoLabel_Regular_Bookings
, hotels.HOT_AutoLabel_Regular_Nights
FROM (
SELECT
kardex.KDX_id
, kardex.KDX_HotelId
, kardex.KDX_type
, kardex.KDX_Status
, (
SELECT
COUNT(bookings.BOO_Id)
FROM
___Bookings bookings
WHERE
bookings.BOO_Status != 'cancel'
AND (
kardex.KDX_Id = bookings.BOO_ClientId
OR
kardex.KDX_Id = bookings.BOO_CompanyId
OR
kardex.KDX_Id = bookings.BOO_BillingId
)
) AS nb_bookings
, (
SELECT
SUM(DATEDIFF(bookings.BOO_DateCO, bookings.BOO_DateCI))
FROM
___Bookings bookings
WHERE
bookings.BOO_Status != 'cancel'
AND (
kardex.KDX_Id = bookings.BOO_ClientId
OR
kardex.KDX_Id = bookings.BOO_CompanyId
OR
kardex.KDX_Id = bookings.BOO_BillingId
)
) AS nb_nights
FROM
___Kardex kardex
)
AS kardex_bookings
INNER JOIN
___Hotels hotels
ON
kardex_bookings.KDX_HotelId = hotels.HOT_HotelId
WHERE
kardex_bookings.KDX_Status = 'active'
AND
# filter out non-bookings
kardex_bookings.nb_bookings != 0
AND
kardex_bookings.nb_nights IS NOT NULL
AND
hotels.HOT_Status = 'active'
ORDER BY
kardex_bookings.KDX_Id ASC
<强>结果
| KDX_id | KDX_type | nb_bookings | nb_nights | HOT_HotelId | HOT_AutoLabel_VIP_Bookings | HOT_AutoLabel_VIP_Nights | HOT_AutoLabel_Regular_Bookings | HOT_AutoLabel_Regular_Nights |
|--------|----------|-------------|-----------|--------------------|----------------------------|--------------------------|--------------------------------|------------------------------|
| 18 | client | 1 | 5 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 19 | client | 2 | 13 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 30 | billing | 1 | 5 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 61 | client | 2 | 9 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
| 63 | company | 1 | 11 | cus_CNHLMiMOzP5cuM | 10 | 15 | 20 | 25 |
<强>演示
答案 1 :(得分：0)
我在这里对您的查询做了一些更改：
SELECT KDX_Id, KDX_Type,nb_bookings,nb_nights,
HOT_HotelId,
HOT_AutoLabel_VIP_Bookings,
HOT_AutoLabel_VIP_Nights,
HOT_AutoLabel_Regular_Bookings,
HOT_AutoLabel_Regular_Nights
FROM (
SELECT KDX_Id, KDX_Type,COUNT(BOO_Id) AS nb_bookings,SUM(DATEDIFF(___Bookings.BOO_DateCO, ___Bookings.BOO_DateCI)) AS nb_nights,
___Kardex.KDX_HotelId
FROM ___Bookings
INNER JOIN ___Kardex
WHERE BOO_Status!='cancel' AND KDX_Status='active'
AND (
KDX_Id = ___Bookings.BOO_ClientId
OR KDX_Id = ___Bookings.BOO_CompanyId
OR KDX_Id = ___Bookings.BOO_BillingId
)
GROUP BY KDX_Id
) aa
JOIN ___Hotels ON aa.KDX_HotelId = ___Hotels.HOT_HotelId AND HOT_Status='active'
这是您想要的结果。请告诉我它是否适合您！ 这是针对禁用'only_full_group_by'sql_mode的情况。