CREATE TABLE foo (
id int IDENTITY(1,1) PRIMARY KEY,
parent_no int DEFAULT 0,
name varchar(255)
);
INSERT INTO foo (name, parent_no) VALUES ('Locations', 0);
INSERT INTO foo (name, parent_no) VALUES ('NSW', 1);
INSERT INTO foo (name, parent_no) VALUES ('QLD', 1);
INSERT INTO foo (name, parent_no) VALUES ('VIC', 1);
INSERT INTO foo (name, parent_no) VALUES ('Sydney', 2);
INSERT INTO foo (name, parent_no) VALUES ('Brisbane', 3);
INSERT INTO foo (name, parent_no) VALUES ('Melbourne', 4);
INSERT INTO foo (name, parent_no) VALUES ('Sydney Head Office', 5);
INSERT INTO foo (name, parent_no) VALUES ('Brisbane Head Office', 6);
INSERT INTO foo (name, parent_no) VALUES ('Melbourne Head Office', 7);
INSERT INTO foo (name, parent_no) VALUES ('Level 21 Martin Place', 8);
INSERT INTO foo (name, parent_no) VALUES ('Level 22 Martin Place', 8);
INSERT INTO foo (name, parent_no) VALUES ('Level 23 Martin Place', 8);
INSERT INTO foo (name, parent_no) VALUES ('Level 24 Martin Place', 8);
INSERT INTO foo (name, parent_no) VALUES ('First Floor', 9);
INSERT INTO foo (name, parent_no) VALUES ('Ground Floor', 9);
INSERT INTO foo (name, parent_no) VALUES ('Second Floor', 9);
如果找到所有父母,如果id = 11 name =“Level 21 Martin Place”
中的代码