Question

下面是我用来替换nagios.cfg中的200多个字符串的shell脚本。

我希望sed替换同一个文件中的所有200个字符串，而是复制内容200次，每次都有一次更改。

    #set -x
    cat partthree | while read  LINE
    do hostnam=`echo $LINE | awk '{print $1}'`
    echo $hostnam
    a=`less hosts | grep $hostnam -A5 | grep -i md5sum | awk '{print $2}'`
    b=`less partthree  | grep $hostnam | awk '{print $2}'`
    echo $a
    echo $b
    sed  "s/$a/$b/g" hosts >> sample
#   sed  "s/$a/$b/g" hosts > sample will change only last occurence
    done

尝试直接使用sed -i“s / $ a / $ b / g”主机

@Expected output：

define host {
        address        sampleaddress
        alias           samplealaias
        host_name       samplealhostname
        _md5sum         def(with replaced string)

}

输出

define host {
   address         sampleaddress
   alias           samplealaias
   host_name       samplealaias
   c8h(origanal string)         def(string that is supposed to replace original c8h value)

}

Answer 1

以下脚本应该完成这项工作。它从最初的hosts文件开始，一个接一个地执行单独的替换。与原始脚本的主要区别在于替换结果不会附加到结果文件，而是在结果文件上就地应用（sed -i）。

# start with 'sample' = 'hosts'
cp hosts sample

# perform replacements one after another in 'sample'
cat partthree | while read LINE ; do
    hostnam=`echo $LINE | awk '{print $1}'`
    a=`less hosts | grep $hostnam -A5 | grep -i md5sum | awk '{print $2}'`
    b=`less partthree  | grep $hostnam | awk '{print $2}'`
    # modify 'sample' in-place
    sed -i "s/$a/$b/g" sample
done

在同一文件上重复使用sed

1 个答案: