Question

我有以下sql查询，我只想要一个列的总和但是它的相同记录的多个回复如下

SELECT 
        b.[Name] 

        sum(td.detailNumber) over () as Totaldetail,
        sum(t.Original) over () as TotalOriginal
    FROM Detail td WITH(NOLOCK)
        inner JOIN Ticket t WITH(NOLOCK) ON t.ID = td.ID
        inner JOIN [system].Branch b WITH(NOLOCK) ON t.BranchID = b.BranchID
        inner JOIN Option mo WITH(NOLOCK) ON OptionID = td.MID

    WHERE (td.ResultDateTime >= '2018/03/10 00:00:00:000' AND td.ResultDateTime <= '2018/03/10 23:59:59:000')
        AND t.BranchID IN (SELECT Data FROM [system].Split('37', ','))

        AND t.Code IN ('RS','AC')

结果

Totaldetail | Totaloriginal
54868       | 78569
54868       | 78569
54868       | 78569
54868       | 78569
54868       | 78569
54868       | 78569
54868       | 78569

正如你在上面看到的那样，它显示了我提供的日期的多行。我只想一次一个结果

Totaldetail | Totaloriginal
    54868   | 78569       //only one record to be shown

Answer 1

首先，删除你OVER条款。 OVER()子句使您的SUM成为一个窗口函数，因此它不会对任何内容进行分组。这就是为什么你看到没有分组的行。

如果您想按每个名称查看聚合，请添加GROUP BY。

SELECT 
    b.[Name],
    sum(td.detailNumber) as Totaldetail,
    sum(t.Original) as TotalOriginal
FROM Detail td WITH(NOLOCK)
    inner JOIN Ticket t WITH(NOLOCK) ON t.ID = td.ID
    inner JOIN [system].Branch b WITH(NOLOCK) ON t.BranchID = b.BranchID
    inner JOIN Option mo WITH(NOLOCK) ON OptionID = td.MID

WHERE (td.ResultDateTime >= '2018/03/10 00:00:00:000' AND td.ResultDateTime <= '2018/03/10 23:59:59:000')
    AND t.BranchID IN (SELECT Data FROM [system].Split('37', ','))
    AND t.Code IN ('RS','AC')
GROUP BY
     b.[Name]

如果您只想查看总计，请删除b。[name]列。

SELECT 
    sum(td.detailNumber) as Totaldetail,
    sum(t.Original) as TotalOriginal
FROM Detail td WITH(NOLOCK)
    inner JOIN Ticket t WITH(NOLOCK) ON t.ID = td.ID
    inner JOIN [system].Branch b WITH(NOLOCK) ON t.BranchID = b.BranchID
    inner JOIN Option mo WITH(NOLOCK) ON OptionID = td.MID

WHERE (td.ResultDateTime >= '2018/03/10 00:00:00:000' AND td.ResultDateTime <= '2018/03/10 23:59:59:000')
    AND t.BranchID IN (SELECT Data FROM [system].Split('37', ','))
    AND t.Code IN ('RS','AC')

SQL sum calc返回多个相同的行而不是单个和

1 个答案: