Question

有可能这样做吗？这是我的代码：

$sponsor1 = "Sponsor 1";
$sponsor2 = "Sponsor 2";
$sponsor3 = "Sponsor 3";
$sponsor4 = "Sponsor 4";
$sponsor5 = "Sponsor 5";
for($i=1;$i<=5;$i++) {
if($sponsor.$i){
echo $sponsor.$i;
echo "<br>";
}}

我希望上面的循环可以像这样显示。我想要这样的东西：

Sponsor 1
Sponsor 2
Sponsor 3
Sponsor 4
Sponsor 5

Answer 1

您可以使用PHP变量变量构建变量，请在此处阅读： http://php.net/manual/en/language.variables.variable.php

$sponsor1 = "Sponsor 1";
$sponsor2 = "Sponsor 2";
$sponsor3 = "Sponsor 3";
$sponsor4 = "Sponsor 4";
$sponsor5 = "Sponsor 5";
for($i=1;$i<=5;$i++) {
   $v = 'sponsor'.$i;
   echo $$v;
   echo "<br>";
}

注意$$v

Answer 2

有三种可能的解决方案：

1.创建数组并迭代它。（的 最佳）

$sponsor_array = ["Sponsor 1","Sponsor 2","Sponsor 3","Sponsor 4","Sponsor 5"]; foreach($sponsor_array as $sponsor){ echo $sponsor; echo PHP_EOL; }

输出： - https://eval.in/974403

2.直接使用for()循环（更好）

<?php for($i=1;$i<=5;$i++) { echo "Sponsor ".$i; echo PHP_EOL; }

输出： - https://eval.in/974401

3.使用Variables variable概念（ 不推荐您的案例 ）

$sponsor1 = "Sponsor 1"; $sponsor2 = "Sponsor 2"; $sponsor3 = "Sponsor 3"; $sponsor4 = "Sponsor 4"; $sponsor5 = "Sponsor 5"; for($i=1;$i<=5;$i++) { $v = 'sponsor'.$i; echo $$v; echo "<br>"; }

输出： - https://eval.in/974405

Answer 3

正确的解决方案是使用数组。

$sponsors = [
    "Sponsor 1",
    "Sponsor 2",
    "etc"
];

foreach ($sponsors as $thisSponsor) {
    echo "$thisSponsor<br />\n";
}

如果由于某种原因您不能直接使用数组，您可以始终执行以下操作：

foreach ([$sponsor1, $sponsor2, $sponsor3, $sponsor4, $sponsor5] as $thisSponsor) {

如何为此循环？

3 个答案: