Question

大家好，我有这个任务：我有一个数组[4,7,3,6,9]，我必须做一个像这样的数组：

[4,7,3,6,9]
[9,4,7,3,6]
[6,9,4,7,3]
[3,6,9,4,7]
[7,3,6,9,4]

我必须创建一个程序，其中数组正在旋转，即使我向数组添加一个新项目，它也应相应地更改。我是JS的新手，1周左右，这是我目前的尝试：

var numbers = [4, 7, 3, 6, 9];
console.log(numbers);
numbers[0] = 9; numbers[1] = 4; numbers[2] = 7; numbers[3] = 3; numbers[4] = 6;
console.log(numbers);
numbers[0] = 6; numbers[1] = 9; numbers[2] = 4; numbers[3] = 7; numbers[4] = 3;
console.log(numbers);
numbers[0] = 3; numbers[1] = 6; numbers[2] = 9; numbers[3] = 4; numbers[4] = 7;
console.log(numbers);
numbers[0] = 7; numbers[1] = 3; numbers[2] = 6; numbers[3] = 9; numbers[4] = 4;
console.log(numbers);

另外在我的脑海里，我有.push，.splice等。我不知道为什么，但我真的觉得javascript不适合我的大脑，哈哈：D

Answer 1

你可以弹出值并取消它。

＆＃13;

var array = [4, 7, 3, 6, 9],
    i = array.length;

while (i--) {
    console.log(array.join(' '));
    array.unshift(array.pop());
}
console.log(array.join(' '));

＆＃13;

Answer 2

您可以将splice与pop结合使用：

＆＃13;

var arr = [4,7,3,6,9];
for(var i=0; i<arr.length-1; i++){
  arr.splice(0, 0, arr.pop())
  console.log(arr)
}

＆＃13;

Answer 3

这是我的解决方案：

var numbers = [4, 7, 3, 6, 9];

for(var i = 0; i < numbers.length; i++) {
    console.log(numbers);
    var lastElement = numbers.pop();
    numbers = [lastElement].concat(numbers);
}

Answer 4

你可以使用swift并推送

function rotate( array , times ){
while( times-- ){
var temp = array.shift();
 array.push( temp )
 }
}

//Test
var players = ['Bob','John','Mack','Malachi'];
rotate( players ,2 )
console.log( players );

javascript旋转数组元素

4 个答案: